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Suma y resta de números mixtos

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Suma y resta de números mixtos - problemas y soluciones

Problema 1

$1\frac{1}{3}=$

$\frac{2}{3}$

$\frac{3}{4}$

$\frac{4}{3}$

$\frac{5}{3}$

Solución:
$1\frac{1}{3}=\frac{3}{3}+\frac{1}{3}=\frac{4}{3}$

Problema 2

[tex]1\frac{1}{4} + 1\frac{3}{4} = [/tex]

Solución:
[tex]1\frac{1}{4} + 1\frac{3}{4} = (1+1) + ( \frac{1}{4} + \frac{3}{4} ) = 2 + \frac{4}{4} = 2 + 1 = 3[/tex]

Problema 3

[tex]3\frac{2}{3} - 2\frac{1}{3} = [/tex]

$1\frac{2}{3}$

$\frac{2}{3}$

$1\frac{1}{3}$

$2\frac{1}{3}$

Solución:
[tex]3\frac{2}{3} - 2\frac{1}{3} = (3 - 2) + \frac{2}{3} - \frac{1}{3} = 1 + \frac{2 - 1}{3} = 1 + \frac{1}{3} = 1\frac{1}{3}[/tex]

Problema 4

[tex]5\frac{1}{2} + 1\frac{1}{2} =[/tex]

Solución:
[tex]5\frac{1}{2} + 1\frac{1}{2} = (5 + 1) + \frac{1}{2} + \frac{1}{2} = 6 + \frac{2}{2} = 6 + 1 = 7[/tex]

Problema 5

[tex]2\frac{5}{6} - 2\frac{1}{6} =[/tex]

$1\frac{2}{3}$

$\frac{4}{3}$

$\frac{1}{3}$

$\frac{2}{3}$

Solución:
[tex]2\frac{5}{6} - 2\frac{1}{6} = (2 - 2) + \frac{5}{6} - \frac{1}{6} = 0 + \frac{5 - 1}{6} = \frac{4}{6} = \frac{2}{3} [/tex]

Problema 6

[tex]2\frac{5}{9} + 2\frac{4}{9} = [/tex]

Solución:
[tex]2\frac{5}{9} + 2\frac{4}{9} = (2 + 2) + \frac{5}{9} + \frac{4}{9} = 4 + \frac{5 + 4}{9} = 4 + \frac{9}{9} = 4 + 1 = 5 [/tex]

Problema 7

[tex]4\frac{2}{7} - 2\frac{5}{7} =[/tex]

$1\frac{3}{7}$

$1\frac{6}{7}$

$\frac{11}{7}$

$2\frac{3}{7}$

Solución:
[tex]4\frac{2}{7} - 2\frac{5}{7} = (4 - 2) + \frac{2}{7} - \frac{5}{7} = 2 + (\frac{-3}{7}) = \frac{14 - 3}{7} = \frac{11}{7} [/tex]

Problema 8

[tex]1\frac{2}{8} + 3\frac{3}{8} = [/tex]

$4\frac{1}{2}$

$4\frac{5}{8}$

$5\frac{5}{8}$

$\frac{25}{8}$

Solución:
[tex]1\frac{2}{8} + 3\frac{3}{8} = (1 + 3) + (\frac{2}{8} + \frac{3}{8}) = 4 + \frac{5}{8} = 4\frac{5}{8}[/tex]

Problema 9

[tex]2\frac{3}{6} + 2\frac{5}{6} =[/tex]

$5\frac{6}{8}$

$5\frac{1}{3}$

$4\frac{8}{6}$

$4\frac{4}{6}$

Solución:
[tex]2\frac{3}{6} + 2\frac{5}{6} = (2 + 2) + (\frac{3}{6} + \frac{5}{6}) = 4 + \frac{8}{6} = 4 + \frac{4}{3} = 4 + 1 \frac{1}{3} = 5\frac{1}{3} [/tex]

Problema 10

[tex]3\frac{4}{9} - 1\frac{2}{9} =[/tex]

$\frac{21}{9}$

$1\frac{2}{9}$

$2\frac{1}{4}$

$\frac{20}{9}$

Solución:
[tex]3\frac{4}{9} - 1\frac{2}{9} = (3 - 1) + (\frac{4}{9} - \frac{2}{9}) = 2 + \frac{2}{9} = \frac{18 + 2}{9} = \frac{20}{9} [/tex]

Problema 11

[tex]2\frac{2}{3} + 4\frac{2}{3} = [/tex]

$6\frac{3}{4}$

$6\frac{1}{3}$

$6\frac{5}{3}$

$7\frac{1}{3}$

Solución:
[tex]2\frac{2}{3} + 4\frac{2}{3} = (2 + 4) + (\frac{2}{3} + \frac{2}{3}) = 6 + \frac{4}{3} = 6 + 1\frac{1}{3} = 7\frac{1}{3} [/tex]

Problema 12

[tex]2\frac{3}{10} + 1\frac{7}{10} =[/tex]

$4$

$2\frac{10}{10}$

$1\frac{10}{10}$

$5$

Solución:
[tex]2\frac{3}{10} + 1\frac{7}{10} = (2 + 1) + ( \frac{3}{10} + \frac{7}{10} ) = 3 + \frac{10}{10} = 3 + 1 = 4 [/tex]

Problema 13

[tex]4\frac{9}{10} - 2\frac{1}{10} =[/tex]

$2\frac{8}{10}$

$2\frac{4}{5}$

$2$

$2\frac{9}{10}$

Solución:
[tex]4\frac{9}{10} - 2\frac{1}{10} = (4 - 2) + ( \frac{9}{10} - \frac{1}{10} ) = 2 + (\frac{8}{10}) = 2 + \frac{4}{5} =2 \frac{4}{5}[/tex]

Problema 14

[tex]4\frac{3}{8} - 3\frac{1}{8} = [/tex]

$1\frac{1}{4}$

$1\frac{1}{8}$

$1\frac{2}{4}$

$1\frac{1}{2}$

Solución:
[tex]4\frac{3}{8} - 3\frac{1}{8} = (4 - 3) + ( \frac{3}{8} - \frac{1}{8} ) = 1 + \frac{2}{8} = 1 + \frac{1}{4} = 1\frac{1}{4}[/tex]

Problema 15

[tex]2\frac{5}{11} + 3\frac{6}{11} = [/tex]

Solución:
[tex]2\frac{5}{11} + 3\frac{6}{11} = (2 + 3) + (\frac{5}{11} + \frac{6}{11}) = 5 + \frac{11}{11} = 5 + 1 = 6 [/tex]

Problema 16

[tex]1\frac{7}{12} + 2\frac{5}{12} = [/tex]

Solución:
[tex]1\frac{7}{12} + 2\frac{5}{12} = (1 + 2) + (\frac{7}{12} + \frac{5}{12}) = 3 + \frac{12}{12} = 3 + 1 = 4 [/tex]

Problema 17

[tex]3\frac{3}{11} - 2\frac{5}{11} = [/tex]

$1\frac{2}{11}$

$1\frac{3}{11}$

$\frac{9}{11}$

$1\frac{7}{11}$

Solución:
[tex]3\frac{3}{11} - 2\frac{5}{11} = (3 - 2) + (\frac{3}{11} - \frac{5}{11}) = 1 + \frac{3 - 5}{11} = 1 + (\frac{-2}{11}) = \frac{11 - 2}{11} = \frac{9}{11} [/tex]

Problema 18

[tex]2\frac{4}{15} - 1\frac{7}{15} = [/tex]

$1\frac{3}{15}$

$\frac{3}{5}$

$1\frac{2}{15}$

$\frac{4}{5}$

Solución:
[tex]2\frac{4}{15} - 1\frac{7}{15} = (2 - 1) + (\frac{4}{15} - \frac{7}{15}) = 1 + \frac{4-7}{15} = 1 + (\frac{-3}{15}) = 1 - \frac{1}{5} = \frac{5 - 1}{5} = \frac{4}{5} [/tex]

Problema 19

[tex]5\frac{1}{3} + 4\frac{1}{3} = [/tex]

$9\frac{1}{3}$

$9\frac{2}{3}$

$\frac{28}{3}$

$8\frac{2}{3}$

Solución:
[tex]5\frac{1}{3} + 4\frac{1}{3} = (5 + 4) + (\frac{1}{3} + \frac{1}{3}) = 9 + \frac{1 + 1}{3} = 9 + \frac{2}{3} = 9\frac{2}{3}[/tex]

Problema 20

[tex]2\frac{7}{20} - 1\frac{3}{20} =[/tex]

$\frac{6}{5}$

$1\frac{2}{5}$

$2\frac{1}{20}$

$1\frac{3}{10}$

Solución:
[tex]2\frac{7}{20} - 1\frac{3}{20} = (2 - 1) + (\frac{7}{20} - {3}{20}) = 1 + \frac{7-3}{20} = 1 + \frac{4}{20} = 1 + \frac{1}{5} = \frac{5 + 1}{5} = \frac{6}{5} [/tex]

Problema 21

[tex]4\frac{1}{5} - 3\frac{3}{5} = [/tex]

Solución:
[tex]4\frac{1}{5} - 3\frac{3}{5} = (4 - 3) + (\frac{1}{5} - \frac{3}{5}) = 1 + (\frac{1-3}{5}) = 1 + \frac{-2}{5} = \frac{5 - 2}{5} = \frac{3}{5} [/tex]

Correcto:

Incorrecto:

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