Fraction Addition and Subtraction - Problems with Solutions

Solution:
[tex]\frac{1}{5}+\frac{2}{5}=\frac{1+2}{5}=\frac{3}{5}[/tex]

Solution:
[tex]\frac{3}{7}+\frac{2}{7}=\frac{3+2}{7}=\frac{5}{7}[/tex]

Solution:
[tex]\frac{1}{3}+\frac{2}{3}=\frac{1+2}{3}=\frac{3}{3}=1[/tex]

Solution:
[tex]\frac{2}{15}+\frac{5}{15}=\frac{2+5}{15}=\frac{7}{15}[/tex]

Solution:
[tex]\frac{8}{11}+\frac{4}{11}=\frac{8+4}{11}=\frac{12}{11}[/tex]

Solution:
[tex]\frac{2}{187}-\frac{2}{187}=\frac{2-2}{187}=\frac{0}{187}=0[/tex]

Solution:
[tex]\frac{13}{39}-\frac{8}{39}=\frac{13-8}{39}=\frac{5}{39}[/tex]

Solution:
[tex]\frac{18}{19}-\frac{11}{19}=\frac{18-11}{19}=\frac{7}{19}[/tex]

Solution:
[tex]\frac{15}{8}-\frac{14}{8}=\frac{15-14}{8}=\frac{1}{8}[/tex]

Solution:
[tex]\frac{19}{27}-\frac{6}{27}=\frac{19-6}{27}=\frac{13}{27}[/tex]

Solution:
[tex]\frac{2}{5}+\frac{-1}{5}=\frac{2+(-1)}{5}=\frac{2-1}{5}=\frac{1}{5}[/tex]

Solution:
[tex]\frac{5}{6}-\frac{10}{6}=\frac{5-10}{6}=\frac{-5}{6}=-\frac{5}{6}[/tex]

Solution:
[tex]\frac{4}{7}-\frac{6}{7}=\frac{4-6}{7}=\frac{-2}{7}=-\frac{2}{7}[/tex]

Solution:
[tex]\frac{14}{13}-\frac{5}{13}=\frac{14-5}{13}=\frac{9}{13}[/tex]

Solution:
[tex]\frac{5}{18}+(-\frac{16}{18})=\frac{5}{18}-\frac{16}{18}=\frac{5-16}{18}=\frac{-11}{18}=-\frac{11}{18}[/tex]

Solution:
[tex]\frac{3}{18}+(-\frac{21}{18})=\frac{3}{18}-\frac{21}{18}=\frac{3-21}{18}=\frac{-18}{18}=-\frac{18}{18}=-1[/tex]

Solution:
[tex]\frac{2}{7}+\frac{3}{7}-\frac{5}{7}=\frac{2+3-5}{7}=\frac{5-5}{7}=\frac{0}{7}=0[/tex]

Solution:
[tex]\frac{8}{91}+\frac{13}{91}=\frac{8+13}{91}=\frac{21}{91}[/tex]

Solution:
[tex]\frac{18}{45}-\frac{5}{45}=\frac{18-5}{45}=\frac{13}{45}[/tex]

Solution:
[tex]\frac{5}{47}+\frac{23}{47}=\frac{5+23}{47}=\frac{28}{47}[/tex]

Solution:
[tex]\frac{43}{56}+\frac{13}{56}=\frac{43+13}{56}=\frac{56}{56}=1[/tex]

Solution:
[tex]\frac{18}{29}+\frac{10}{29}=\frac{18+10}{29}=\frac{28}{29}[/tex]

Solution:
[tex]\frac{15}{10}-\frac{8}{10}=\frac{15-8}{10}=\frac{7}{10}[/tex]

Solution:
[tex]\frac{5}{31}-\frac{4}{31}=\frac{5-4}{31}=\frac{1}{31}[/tex]