Fraction Addition and Subtraction: Problems with Solutions

Solution:
[tex]\frac{1}{5}+\frac{2}{5}=\frac{1+2}{5}=\frac{3}{5}[/tex]

Solution:
[tex]\frac{3}{7}+\frac{2}{7}=\frac{3+2}{7}=\frac{5}{7}[/tex]

Solution:
[tex]\frac{1}{3}+\frac{2}{3}=\frac{1+2}{3}=\frac{3}{3}=1[/tex]

Solution:
[tex]\frac{2}{15}+\frac{5}{15}=\frac{2+5}{15}=\frac{7}{15}[/tex]

Solution:
[tex]\frac{8}{11}+\frac{4}{11}=\frac{8+4}{11}=\frac{12}{11}[/tex]

Solution:
[tex]\frac{2}{187}-\frac{2}{187}=\frac{2-2}{187}=\frac{0}{187}=0[/tex]

Solution:
[tex]\frac{13}{39}-\frac{8}{39}=\frac{13-8}{39}=\frac{5}{39}[/tex]

Solution:
[tex]\frac{18}{19}-\frac{11}{19}=\frac{18-11}{19}=\frac{7}{19}[/tex]

Solution:
[tex]\frac{15}{8}-\frac{14}{8}=\frac{15-14}{8}=\frac{1}{8}[/tex]

Solution:
[tex]\frac{19}{27}-\frac{6}{27}=\frac{19-6}{27}=\frac{13}{27}[/tex]

Solution:
[tex]\frac{2}{5}+\frac{1}{5}=\frac{2+1}{5}=\frac{2+1}{5}=\frac{3}{5}[/tex]

Solution:
[tex]\frac{5}{6}+\frac{10}{6}=\frac{5+10}{6}=\frac{15}{6}=\frac{5\times 3}{2 \times 3}=\frac{5}{2}[/tex]

Solution:
[tex]\frac{6}{7}-\frac{4}{7}=\frac{6-4}{7}=\frac{2}{7}[/tex]

Solution:
[tex]\frac{14}{13}-\frac{5}{13}=\frac{14-5}{13}=\frac{9}{13}[/tex]

Solution:
[tex]\frac{3}{18}+\frac{15}{18}=\frac{18}{18}=1[/tex]

Solution:
[tex]\frac{2}{7}+\frac{3}{7}-\frac{5}{7}=\frac{2+3-5}{7}=\frac{5-5}{7}=\frac{0}{7}=0[/tex]

Solution:
[tex]\frac{8}{91}+\frac{13}{91}=\frac{8+13}{91}=\frac{21}{91}[/tex]

Solution:
[tex]\frac{15}{45}-\frac{5}{45}=\frac{10}{45}=\frac{5\times 2}{5 \times 9}=\frac{5}{5}\times \frac{2}{9}=1\times \frac{2}{9} = \frac{2}{9}[/tex]

Solution:
[tex]\frac{5}{6}+\frac{4}{6} = \frac{9}{6}=\frac{3\times 3}{2 \times 3} = \frac{3}{2}=1\frac{1}{2}[/tex]

Solution:
[tex]\frac{43}{56}+\frac{13}{56}=\frac{43+13}{56}=\frac{56}{56}=1[/tex]

Solution:
[tex]\frac{18}{29}+\frac{10}{29}=\frac{18+10}{29}=\frac{28}{29}[/tex]

Solution:
[tex]\frac{5}{18}-\frac{1}{18} = \frac{4}{18}=\frac{2\times 2}{2 \times 9}=\frac{2}{2}\times \frac{2}{9}=1\times \frac{2}{9}=\frac{2}{9}[/tex]

Solution:
[tex]\frac{5}{18}+\frac{16}{18}=\frac{5}{18}+\frac{16}{18}=\frac{5+16}{18}=\frac{21}{18}=\frac{3 \times 7}{3 \times 6} = \frac{7}{6}=1\frac{1}{6}[/tex]

Solution:
[tex]\frac{6}{10}-\frac{1}{10}=\frac{5}{10}=\frac{5}{2\times 5}=\frac{1}{2}\times \frac{5}{5}=\frac{1}{2} \times 1 = \frac{1}{2}[/tex]