Area of Squares and Rectangles: Problems with Solutions

Solution:
Area of a rectangle is L × W where L is the length and W is the width
6 × 4 = 24 in².

Solution:
The sides of а square are equal size. The square's area is a × a where a is the side of the square.
5 × 5 = 25

Solution:
Area = a × a where a is the length of a side
a × a = 16
4 × 4 = 16
a = 4

Solution:
Area = L × W
45 = 9 × W
W = 45 ÷ 9 = 5

Solution:
Perimeter is 4 × a where a is the side of the square
4 × a =24
a = 24 ÷ 4 = 6
Area = a × a = 6 × 6 = 36 cm²

Solution:
L = 12
W = 12 - 5 = 7
Area = L × W = 12 × 7 = 84 cm²

Solution:
L = 12
W = 12 ÷ 3 = 4
Area = L × W = 12 × 4 = 48 cm²

Solution:
The area of the first rectangle is L × W = 6 × 4 = 24 cm²
The new length is 6 + 2 = 8 cm
8 × W = 24 then W = 24 ÷ 8 = 3 cm

Solution:
The area of the square is 2 × 2 = 4 cm²
The area of the rectangle is L × W = 24 × 8 = 192 cm²
The number of squares is 192 ÷ 4 = 48

Solution:
The area of the square is 6 × 6 =36 cm²
The area of the rectangle is L × W. Because the areas are equal L × W = 36
L × 4 = 36
L = 36 ÷ 4 = 9 cm

Solution:
The area of the first square is 5 × 5 = 25 cm²
The area of the new square is 10 × 10 = 100 cm²
The area is 4 times bigger

Solution:
The field is a rectangle whose length is 25 meters and width is 12 meters. The area is L × W = 25 × 12 = 25 × 4 × 3 = 100 × 3 = 300 m²
The field covered by the house is a square with the side of 9 meters. The area is 9 × 9 = 81 m²
The garden's area will be 300 - 81 = 219 m²

Solution:
The area of the blue zone is half of the rectangle's area.
Area = (L × W) ÷ 2 = (12 × 9) ÷ 2 = 108 ÷ 2 = 54 m²

Solution:
[AF] = 24 m
[DE] = 15 m
[BC] = [AF] - [DE] = 9 m
[FE] = 20 m
[AB] = 9 m
[CD] = [FE] - [AB] = 11 m
The area of the red zone is equal to the difference between the area of the rectangle with a length of 24 meters and a width of 20 meters and the area of the rectangle with a length of 11 meters and a width of 9 meters
Area = (24 × 20) - ( 11 × 9) = 480 - 99 = 381 m²

Solution:
The area of the park is 30 × 30 = 900 m²
The alley is shaped like a rectangle with a length of 30 m and a width of 2 m. Area is L × W = 30 × 2 = 60 m²
The green zone has an area of 900 - 60 = 840 m²

Solution:
The length of the screen is 80 - (5 + 5) = 80 - 10 = 70 cm, the width of the screen is 50 - (5 + 5) = 50 - 10 = 40 cm
The area of the screen is 70 × 40 = 2800 cm²

Solution:
Because there are 5 squares on the width of the rectangle and 7 squares on its length, then the side of the square is 2 cm. The area of a square is 4 cm². There are 18 blue squares, so their area will be 4 × 18 = 72 cm²

Solution:
The area of the rectangle ABCD is 48 cm². Rectangle ABCD is split into 4 equal rectangles. Thus, the area of rectangle AMOQ is 12 cm². Rectangle AMOQ is split into 4 equal rectangles. The area of a blue rectangle is 3 cm². The total area of the 2 blue rectangles is 6 cm².

Solution:
The area of the square is 4 cm². It's split in 4 equal squares. The area of a small square is 1 cm², the area of the rectangle is 54 cm², so the area of the red zone is 54 - 1 = 53 cm².

Solution:
The sides of the box are equal in pairs. Two of the sides have edges of 10 cm and 6 cm.
Their area is (10 × 6) × 2 = 60 × 2 = 120 cm²
Two of the sides have edges of 10 cm and 8 cm.
Their area is (10 × 8) × 2 = 80 × 2 = 160 cm²
Two of the sides have edges of 8 cm and 6 cm.
Their area is (8 × 6) × 2 = 48 × 2 = 96 cm²
The total area is 120 + 160 + 96 = 376 cm²