Home
Math Forum/Help
Problem Solver
Practice
Worksheets
Tests
Algebra
Geometry
College Math
History
Games

Home
Tests (Quizzes)
Dividing by Monomial

Dividing Polynomial by Monomial

Complete the test and get an award.

Question 1

Simplify [tex] \frac{81b^3}{9b^2} [/tex]?

[tex] \frac{1}{3b} [/tex]

[tex] 3b [/tex]

[tex] \frac{b}{3} [/tex]

[tex] b^3 [/tex]

Question 2

Simplify [tex] \frac{34a^3b^4}{17a^4b} [/tex]?

[tex] \frac{2b^3}{a} [/tex]

[tex] \frac{2b^2}{a} [/tex]

[tex] \frac{2a^3}{b} [/tex]

[tex] \frac{2a^2}{b} [/tex]

Question 3

Which of the following is true?

[tex] \frac{x^2y}{2x^2y^2} = \frac{x}{2y} [/tex]

[tex] \frac{x^2y}{x^3y^5} = \frac{2x}{y^4} [/tex]

[tex] \frac{x^2y}{2x^2y^2} = \frac{1}{2y} [/tex]

[tex] \frac{x^4y^3}{x^2y^2} = \frac{1}{xy} [/tex]

Question 4

Simplify [tex] \frac{3a^2b+2a^3b^3}{a} [/tex]?

[tex] 3ab^2+2a^2b^3 [/tex]

[tex] 3ab+2ab^3 [/tex]

[tex] 3ab+2a^2b^2 [/tex]

[tex] 3ab+2a^2b^3 [/tex]

Question 5

Simplify [tex] \frac{2rs+st}{-s^2} [/tex]?

[tex] \frac{r+t}{-s} [/tex]

[tex] \frac{2r+t}{-s} [/tex]

[tex] \frac{r^2+t}{-s} [/tex]

[tex] \frac{2r+t}{s} [/tex]

Question 6

Which of the following is false?

[tex] \frac{x^3-5x^2}{-x}=-x^2+5x [/tex]

[tex] \frac{x^7-5x^8}{-x^2}=-x^5+5x^6 [/tex]

[tex] \frac{4x^3-8x^2}{-2x^2}=-2x+4 [/tex]

[tex] \frac{x^3-5x^2}{-x}=-x^2-5x [/tex]

Question 7

Simplify [tex] \frac{a^3b^2cd^4}{a^2b^3c^2d^3} [/tex]?

[tex] \frac{ad}{bc} [/tex]

[tex] \frac{ab}{cd} [/tex]

[tex] \frac{ac}{bd} [/tex]

[tex] \frac{bd}{ac} [/tex]

Question 8

Simplify [tex] \frac{6x+15a+21y+24}{3} [/tex]?

[tex] 3x+15a+7y+8 [/tex]

[tex] 2x+5a+8y+7 [/tex]

[tex] 2x+5a+7y+8 [/tex]

[tex] 3x+5a+7y+8 [/tex]

Question 9

Which of the following is false?

[tex] \frac{2x^3-x^2}{x^2}=2x-1 [/tex]

[tex] \frac{y^3x}{-y^3x^2}=\frac{1}{x} [/tex]

[tex] -\frac{x^2y-xy^2}{xy} =y-x [/tex]

[tex] -\frac{a^2b^2c^2}{-ac}=ab^2c [/tex]

Question 10

Which of the following is true?

[tex] \frac{as+bs^2}{3s} = \frac{a+bs}{3} [/tex]

[tex] \frac{as^2+bs}{2s}= \frac{as+bs^2}{2} [/tex]

[tex] \frac{abc+bc^2}{c}=ab+bc^2 [/tex]

[tex] \frac{ab^2c^2}{a^2bc}=\frac{bc}{a^2} [/tex]

Loading...

Feedback Contact email:

Follow us on Twitter Facebook

Author Math10 Banners
Copyright © 2005 - 2024