Addition and Subtraction of Mixed Numbers with Like Denominators, Fifth Grade Test

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This free test is designed for math students in fifth grade. In this test, problems require addition and subtraction of mixed numbers. Fractions have like denominators.
The answers must be provided in simplified form not a mixed fraction.
For Example: [tex]1\frac{1}{3} = 4/3[/tex]
4/3 is the acceptable answer.
The answer must be in improper fractions NOT a mixed number.
Problem #1
[tex]1\frac{1}{2} + 2\frac{1}{2} = ?[/tex]
Answer:
Problem #2
[tex]3\frac{1}{3} - 1\frac{2}{3} = ?[/tex]
Answer:
Problem #3
[tex]1\frac{1}{3} + 1\frac{1}{3} = ?[/tex]
Answer:
Problem #4
[tex]1\frac{2}{3} - 1\frac{1}{3} = ?[/tex]
Answer:
Problem #5
[tex]3\frac{1}{4} + 1\frac{3}{4} = ?[/tex]
Answer:
Problem #6
[tex]2\frac{3}{4} + 1\frac{1}{4} = ?[/tex]
Answer:
Problem #7
[tex]3\frac{2}{5} - 2\frac{2}{5} = ?[/tex]
Answer:
Problem #8
[tex]4\frac{1}{5} - 3\frac{3}{5} = ?[/tex]
Answer:
Problem #9
[tex]3\frac{3}{4} + 2\frac{1}{4} = ?[/tex]
Answer:
Problem #10
[tex]2\frac{1}{2} + 5\frac{1}{2} = ?[/tex]
Answer:
Problem #11
[tex]6\frac{2}{3} - 3\frac{1}{3} = ?[/tex]
Answer:
Problem #12
[tex]4\frac{3}{4} - 1\frac{1}{4} = ?[/tex]
Answer:
Problem #13
[tex]5\frac{1}{6} - 3\frac{5}{6} = ?[/tex]
Answer:
Problem #14
[tex]3\frac{3}{6} + 2\frac{1}{6} = ?[/tex]
Answer:
Problem #15
[tex]2\frac{1}{7} + 1\frac{3}{7} = ?[/tex]
Answer:
Problem #16
[tex]4\frac{2}{7} - 2\frac{3}{7} = ?[/tex]
Answer:
Problem #17
[tex]3\frac{1}{3} + 2\frac{2}{3} - 1\frac{1}{3} = ?[/tex]
Answer:
Problem #18
[tex]3\frac{1}{3} - 2\frac{2}{3} + 1\frac{1}{3} = ?[/tex]
Answer:
Problem #19
[tex]3\frac{3}{4} - 2\frac{1}{4} + 1\frac{3}{4} = ?[/tex]
Answer:



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