Radical, What is Radical
Let us take the number 9. Nine divided by 3 equals to the divider 3 => 9/3 = 3, so 3.3 = 9 or 32 = 9. Let us take another number, 27 this time, 27 = 3.3.3 = 33. So we found that 9 and 27 are actually 3 with exponent 2 and 3.
Basically what radical is, is a function which finds a divider, of the argument, which upped on exponent gives us the argument. Sometimes this divider is not a rational number. The radical is actually the opposite function of an exponent. It even can be write down with the help of an exponent.
So in our case the square(2nd) root of 9 is 3, √9 and the third root of 27 is 3 = 3√27
If a is positive real number then the equation x2 = a has two solutions: x = +√a or x = -√a.
$\sqrt[2]{x}$ is $\sqrt{x}$
If a is real number then the equation x3 = a has only one solution => x = 3√a.
With the help of the equtions above we solve square and cubic equations.
A root can be write down with the help of an exponent, the following rule applies:
Radical Formulas
If n is odd:
$\sqrt[n]{x^n}=x$
If n is even:
$\sqrt[n]{x^n}=|x|$ - the absolute value of x
Example: $\sqrt[3]{x^3}=x$ but $\sqrt[4]{x^4}=|x|$
$\sqrt[n]{a \cdot b}=\sqrt[n]{a}\cdot \sqrt[n]{b}$
Proof: let's have n√ab = (ab)1/n, which from the basic formula up of the exponent, comes to a1/n.b1/n, or n√an√b
$\sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}$
Proof: n√a/b = (a/b)1/n and from the basic equations of the exponent, comes to a1/n/b1/n, or n√a/n√b
$\sqrt[n]{\sqrt[m]{a}}=\sqrt[n\cdot m]{a}$
Proof: if you have n√m√a that equals to n√a1/m, which equals to (a1/m)1/n and from the basic equations of the exponent, comes to a1/(m.n), or n . m√a
Radical monotony
Graph of square root
Graph of third root
More about radicals in the maths forum
- Trying to understand reality with a unified field hypothesis
- Help questions
- Find all the pairs
- Math circles and parallelograms
- Restoring the Proper Balance to Earth's Carbon Cycle
- Our world is not a closed system?
- A complete proof of the Collatz conjecture
- Math Has A Fatal Flaw?
- Induction
- P versus NP Problem: Is P = NP?