Divisors and Multiples
Divisibility of a Sum and a Difference
Adding and multiplying whole numbers always works. Dividing doesn't always come out even: 20 ÷ 4 = 5, but 20 ÷ 3 = 6 R 2. This page shows how to tell whether a division leaves a remainder – often without dividing at all. For quick tests on the digits, see the divisibility rules.
Divisors and multiples
If a ÷ b leaves no remainder, then a is a multiple of b (a is divisible by b), and b is a divisor, or factor, of a.
12 ÷ 3 = 4 → 12 is a multiple of 3, and 3 is a divisor of 12.
12 ÷ 5 = 2 R 2 → 12 is not a multiple of 5, and 5 is not a divisor of 12.
| Number | Its divisors | Its multiples |
|---|---|---|
| 7 | 1, 7 | 7, 14, 21, 28, 35, … |
| 12 | 1, 2, 3, 4, 6, 12 | 12, 24, 36, 48, 60, … |
| 15 | 1, 3, 5, 15 | 15, 30, 45, 60, 75, … |
| 18 | 1, 2, 3, 6, 9, 18 | 18, 36, 54, 72, 90, … |
- 1 is a divisor of every number.
- Every number is a divisor and a multiple of itself.
- A number has only a few divisors, but its multiples never end.
Example: find all divisors of 36
Write 36 as a product of two numbers in every possible way, starting with 1:
1 × 36 2 × 18 3 × 12 4 × 9 6 × 6
5 doesn't work (36 ÷ 5 = 7 R 1), and once the two factors meet at 6 × 6 you can stop.
Divisors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36.
Divisibility of a sum
If every addend is divisible by a number, the sum is also divisible by that number.
6 + 14 = 20 – all divisible by 2
12 + 18 + 30 = 60 – all divisible by 6
25 + 50 + 75 = 150 – all divisible by 25
Why? 12 = 6 × 2 and 18 = 6 × 3, so 12 + 18 = 6 × 2 + 6 × 3 = 6 × 5. The sum is still a whole number of sixes.
If all addends but one are divisible by a number, the sum is not divisible by that number.
By 3: 15 ✓ + 10 ✗ = 25 ✗
By 5: 10 ✓ + 30 ✓ + 8 ✗ = 48 ✗
Careful: if two or more addends are not divisible, the rule tells you nothing – check the sum itself. By 4: 7 + 5 = 12 is divisible, but 7 + 2 = 9 is not.
Check without dividing
Split the number into a round part that is clearly divisible, plus a small part.
| Is it divisible? | Split it | Answer |
|---|---|---|
| 742 by 7 | 700 ✓ + 42 ✓ | Yes (742 = 7 × 106) |
| 1,854 by 6 | 1,800 ✓ + 54 ✓ | Yes (1,854 = 6 × 309) |
| 1,236 by 12 | 1,200 ✓ + 36 ✓ | Yes (1,236 = 12 × 103) |
| 4,545 by 45 | 4,500 ✓ + 45 ✓ | Yes (4,545 = 45 × 101) |
| 3,927 by 13 | 3,900 ✓ + 27 ✗ | No |
Divisibility of a difference
If the minuend and the subtrahend are both divisible by a number, the difference is also divisible by that number.
40 − 12 = 28 – all divisible by 4
90 − 36 = 54 – all divisible by 9
If exactly one of them is not divisible by a number, the difference is not divisible by that number.
By 10: 40 ✓ − 12 ✗ = 28 ✗
By 6: 40 ✗ − 12 ✓ = 28 ✗
Careful: if neither number is divisible, check the difference itself. By 3: 11 − 5 = 6 is divisible, but 11 − 4 = 7 is not.
Check without dividing
Go up to a round number that is clearly divisible, then subtract the small part.
| Is it divisible? | Split it | Answer |
|---|---|---|
| 792 by 8 | 800 ✓ − 8 ✓ | Yes (792 = 8 × 99) |
| 686 by 7 | 700 ✓ − 14 ✓ | Yes (686 = 7 × 98) |
| 1,176 by 24 | 1,200 ✓ − 24 ✓ | Yes (1,176 = 24 × 49) |
| 2,340 by 13 | 2,600 ✓ − 260 ✓ | Yes (2,340 = 13 × 180) |
| 395 by 4 | 400 ✓ − 5 ✗ | No |
Summary
| The numbers you add or subtract | The sum or difference |
|---|---|
| are all divisible by a number | is divisible by that number |
| are all divisible except one | is not divisible |
| include two or more that are not divisible | may or may not be – check it |
Try it yourself
Click a question to see the answer.
1. List all divisors of 24.
1 × 24, 2 × 12, 3 × 8, 4 × 6
Divisors: 1, 2, 3, 4, 6, 8, 12, 24
2. Write the first five multiples of 9.
9, 18, 27, 36, 45
3. Without dividing, is 2,114 divisible by 7?
2,114 = 2,100 + 14, and both are divisible by 7.
Yes (2,114 = 7 × 302)
4. Without dividing, is 1,188 divisible by 12?
1,188 = 1,200 − 12, and both are divisible by 12.
Yes (1,188 = 12 × 99)
5. Without dividing, is 1,445 divisible by 7?
1,445 = 1,400 + 45. 1,400 is divisible by 7, but 45 is not.
No
6. True or false: 9 + 15 = 24 and 24 is divisible by 4, so 9 and 15 must be divisible by 4.
False. Neither 9 nor 15 is divisible by 4. The rule only works one way: divisible addends give a divisible sum, not the other way around.

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