Divisibility by 5
A number is divisible by 5 if its last digit is 0 or 5.
Examples
| Number | Last digit | Divisible by 5? |
|---|---|---|
| 425 | 5 | Yes |
| 428 | 8 | No |
| 1,760 | 0 | Yes |
| 3,945 | 5 | Yes |
| 1,404 | 4 | No |
| 55,551 | 1 | No |
A number that ends in 0 is divisible by 2, by 5 and by 10. For example, 1,760 = 176 × 10.
Why it works
Split the number into tens and ones: 425 = 420 + 5.
420 is 42 tens, and 10 = 5 × 2, so 420 is divisible by 5. Only the last digit is left to check:
425 = 420 ✓ + 5 ✓ → divisible by 5
428 = 420 ✓ + 8 ✗ → not divisible by 5
This uses the rule for the divisibility of a sum.
Careful: ending in 5 does not mean divisible by 25. 35 ends in 5, but 35 ÷ 25 = 1 R 10. See divisibility by 25.
Bonus: quick tricks with 5
5 is half of 10, so you can work with 10 and 2 instead.
| Task | Trick | Examples |
|---|---|---|
| Divide by 5 | Multiply by 2, then divide by 10 | 415 ÷ 5: 415 × 2 = 830, 830 ÷ 10 = 83 342 ÷ 5: 342 × 2 = 684, 684 ÷ 10 = 68.4 |
| Multiply by 5 | Divide by 2, then multiply by 10 | 62 × 5: 62 ÷ 2 = 31, 31 × 10 = 310 47 × 5: 47 ÷ 2 = 23.5, 23.5 × 10 = 235 |
| Square a two-digit number ending in 5 | Multiply the tens digit by the next number, then write 25 after the result | 352: 3 × 4 = 12 → 1,225 852: 8 × 9 = 72 → 7,225 |
Try it yourself
Click a question to see the answer.
1. Which of these numbers are divisible by 5: 135, 552, 2,000, 7,005, 9,999?
135, 2,000 and 7,005 – they end in 5, 0 and 5.
2. Which digits can go in the box so that 47 is divisible by 5?
0 or 5: 470 and 475.
3. Divide quickly: 235 ÷ 5
235 × 2 = 470, 470 ÷ 10 = 47
4. Multiply quickly: 86 × 5
86 ÷ 2 = 43, 43 × 10 = 430
5. Square quickly: 452
4 × 5 = 20, then write 25 after it: 2,025
6. A number is divisible by both 2 and 5. What must its last digit be?
0. For 2 the last digit must be 0, 2, 4, 6 or 8; for 5 it must be 0 or 5. Only 0 is on both lists.

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