Andy » Сб май 09, 2015 8:05 am
[tex]\int\sin^4 x\cos^5 xdx=\left(\sin x=y,~x=\arcsin y,~dx=\frac{dy}{\sqrt{1-y^2}},~\cos x=\sqrt{1-y^2}\right)=\int y^4\cdot\left(\sqrt{1-y^2}\right)^5\cdot\frac{dy}{\sqrt{1-y^2}}=[/tex]
[tex]=\int y^4\left(1-y^2\right)dy=\int y^4\left(1-2y^2+y^4\right)dy=\int\left(y^4-2y^6+y^8\right)dy=\frac{1}{5}y^5-\frac{2}{7}y^7+\frac{1}{9}y^9+C=[/tex]
[tex]=\frac{1}{5}\sin^5 x-\frac{2}{7}\sin^7 x+\frac{1}{9}\sin^9 x+C.[/tex]