Maths

[Guest]

The length of the rectangle is one more than the width. If the dimensions are both decreased by 2 units, the area of the new rectangle is 30 sq. units less than the area of the original rectangle. Find the area of the original rectangle.

[romsek]

[tex]l = w+1\\
(l-2)(w-2) = l w - 30\\

(w-1)(w-2) = (w+1)w-30\\

w^2 -3w+2 = w^2 + w - 30\\
32 = 4w\\
w=8\\
l=9\\
area = l w = 72[/tex]