Square roots

Linear, quadratic, module, parametric equations

Square roots

Postby Guest » Sun Dec 22, 2019 4:06 pm

Can this equation be solved for B when B^2 is a very large number, and both A and B^2 are known, without having to take the square root of B^2 ?

B^2 = A^2 + (B+A)x(B-A) ? Where A is 7, and B^2 is 45,369

Thanks for the help.
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Re: Square roots

Postby Guest » Tue Dec 24, 2019 3:01 am

The right side is

A^2+(B+A)(B-A)=A^2+B^2-A^2=B^2
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Re: Square roots

Postby HallsofIvy » Wed Jan 08, 2020 12:09 pm

B^2= A^2+ (B- A)(B+ A) is the same as B^2- A^2= (B- A)(B+ A) which is an identity- it is true for all A and B. Knowing that A= 7 doesn't help. If B^2= 45369 then B is the square root of 45369. The only way to determine B is to take the square root.

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Re: Square roots

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