Math - Algebra

Linear, quadratic, module, parametric equations

Math - Algebra

Postby Guest » Wed Feb 27, 2019 1:18 pm

Please, help me:D
I can't solve this equation...
[tex](x + 2)^{4}[/tex] + [tex](x + 4)^{4}[/tex] = 82

Very intresting for me!
Thanks.
Guest
 

Re: Math - Algebra

Postby Guest » Fri Mar 01, 2019 3:52 pm

You can simplify this a little by letting y= x+ 4 so that x+ 2= y- 2 and then [tex](x+ 2)^4+ (x+ 4)^4= (y- 2)^4+ y^4=[/tex][tex]y^4- 8y^3+ 24y^2- 32x+ 16+ y^4= 2y^4- 8y^3+ 24y^2- 32y+ 16= 82[/tex]. Subtracting 82 from both sides, [tex]2y^4- 8y^3+ 24y^2- 32y+ 66= 0[/tex]. Divide by 2: [tex]y^4- 4y^3+ 12y^2- 16y+ 33= 0[/tex]. By the "rational root theorem" the only possible rational roots are 1, -1, 33, and -33. Evaluating the polynomial at those values shows that -33 is the only rational number root.
Guest
 


Return to Equations



Who is online

Users browsing this forum: No registered users and 2 guests