Solution for X

Linear, quadratic, module, parametric equations

Solution for X

Postby Guest » Wed Jan 23, 2019 4:11 am

I have a question, i've been trying to solve for x with these equations, but i can't find the solution. Can someone help me here?

.182*ln([tex]\frac{1-(.121+.013*ln(x))}{.968}[/tex]) = .98*ln([tex]\frac{1}{1-x}[/tex])
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Re: Solution for X

Postby Guest » Tue Feb 26, 2019 6:42 pm

[tex]x ln(A)= yln(B)[/tex] is the same as [tex]ln(A^x)= ln(B^y)[/tex] and, since logarithm is a one-to-one function, A^x= B^y. So this equation can be "reduced" to [tex]\frac{(0.879- .13ln(x))^{0.182}}{0.994}= (1- x)^{0.98}[/tex]. With that logarithm on one side of the equation and no logarithm on the other, you will not be able to write a solution in terms of elementary functions.
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