Hi, we were rearranging formula to make [tex]x[/tex] the subject and for one equation our answer was different to our lecturers, but they failed to explain why they were right and we were wrong- if someone could that would be great.

When making [tex]x[/tex] the subject we're told to "do the opposite" to achieve this.

The equation with our working:

[tex]y=5(x+3)[/tex]

[tex]\frac{y}{5}=x+3[/tex]

[tex]\frac{y}{5}-3=x[/tex]

Replacing [tex]x[/tex] with 2 as an example to test our result:

[tex]y=5(2+3)[/tex] (or) [tex]y=5[/tex]x[tex]5[/tex] (or) [tex]y=25[/tex]

[tex]\frac{25}{5}=5[/tex], [tex]-3=2[/tex], [tex]x=2[/tex]