Parabola

Linear, quadratic, module, parametric equations

Parabola

Postby Guest » Tue Jul 17, 2018 3:37 pm

Hi, I'm trying to work out the x-intercepts of the parabola of the quadratic equation y = - x^2/8 + 11x/8 + 3/2. Anyone got any advice please, thanks.
Guest
 

Re: Parabola

Postby Guest » Fri Jul 20, 2018 6:04 am

You have to solve the equation
[tex]- \frac{x^2}{8} + \frac{11x}{8} + \frac32 = 0[/tex]

Multiply the both sides by 8
[tex]- x^2 + 11x + 12 = 0[/tex]

[tex]D = 12^2 - 4\cdot 11 \cdot(-1) = 144 + 44 = 188[/tex]

The roots are
[tex]x_{1,2} = \frac{-11 \pm \sqrt{188}}{-2}[/tex]
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