Equation: 2/(x-5) - 1/(x+1) = 1

[Equation]

Solve the equation

[tex]\frac{2}{x-5} - \frac{1}{x+1 } = 1[/tex]

[mathbuddy]

[tex]\frac{2}{x-5} - \frac{1}{x+1 } = 1[/tex]

The least common denominator is (x - 5)(x + 1), hence multiply the equation with it on both sides

{[tex]\frac{2}{x-5} - \frac{1}{x+1 } = 1[/tex]}(x - 5)(x + 1)

[tex]2(x + 1) - 1(x -5) = (x - 5)(x + 1)[/tex]

Now open the brackets and solve the quadratic equation.

[amit28it]

Equation: 2/(x-5) - 1/(x+1) = 1

Ans:-
[2(x+1) - (x - 5)]/(x-5)(x+1) = 1

[2x + 2 - x +5] = (x - 5)(x +1)

x + 7 = x^2 + x -5x - 5

x^2 -5x -12 = 0
So now you can solve it .

[Guest]

Can you help me solving this equation, please?
[tex]\frac{2}{x^2-1} - \frac{4}{x - 1} = 3[/tex]

[Guest]

Can you help me solving this equation, please?
[tex]\frac{2}{x^2-1} - \frac{4}{x - 1} = 3[/tex]

2/(x-1)(x+1) - 4/(x-1) = 3

[2 -4(x+1)]/(x^2-1) = 3

[2 - 4x -4] = 3x^2- 3

-2 -4x = 3x^2 - 3

3x^2 +4x -1 = 0

Now you can solve it ............ok

[manoj9585]

Equations is : 2/(x-5) - 1/(x+1) = 1

Here is a solution for equation :
[2(x+1) - 1(x-5)]/(x-5)(x+1) = 1

2x + 2 - x + 5 = (x+1)(x-5)

x + 7 = x^2 + x - 5x -5

x is cancel from both of side.

Final equation is :

x^2 - 5x - 12 = 0

Now, you can solve it easily....
Hope this will help you.

[perfectmath]

Equations is : 2/(x-5) - 1/(x+1) = 1

Here is a solution for equation :
[2(x+1) - 1(x-5)]/(x-5)(x+1) = 1

2x + 2 - x + 5 = (x+1)(x-5)

x + 7 = x^2 + x - 5x -5

x is cancel from both of side.

Final equation is :

x^2 - 5x - 12 = 0

Now, you can solve it easily....
Hope this will help you.

I found [tex]x=6.77200187265877,x=-1.77200187265877.[/tex]

[perfectmath]

Can you help me solving this equation, please?
[tex]\frac{2}{x^2-1} - \frac{4}{x - 1} = 3[/tex]

2/(x-1)(x+1) - 4/(x-1) = 3

[2 -4(x+1)]/(x^2-1) = 3

[2 - 4x -4] = 3x^2- 3

-2 -4x = 3x^2 - 3

3x^2 +4x -1 = 0

Now you can solve it ............ok

I found [tex]x=0.21525043702153,x=-1.54858377035486.[/tex]