Function f(x) has exactly one real root

Function f(x) has exactly one real root

Postby markosheehan » Thu Jun 16, 2016 5:13 am

f:x x³+(1-k²)x+k is a cubic function where k is a constant.1. show that -k is a root of f.2.find in terms of k the other two roots of f.3 find the set of values of k for which f has exactly one real root.

i think i know how to do the first question just sub in k for x and it should equal 0 but i dont know how to do the second and third qustion.
markosheehan
 
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Re: algebra

Postby Guest » Thu Jun 16, 2016 7:09 pm

For 2 use polynomial long division to factor out the (x+k) factor.
https://en.wikipedia.org/wiki/Polynomial_long_division
This should leave a quadratic term which you can solve using the quadratic formula.

For 3 find the values of k such that the terms inside the square root part are negative.

Hope this helped,

R. Baber.
Guest
 


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