Solve for x

Solve for x

Postby nycmath » Fri Oct 02, 2026 6:40 pm

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Re: Solve for x

Postby Eigenvalue » Fri Oct 02, 2026 9:49 pm

[tex]5^{x-1}[/tex]=[tex]5^{x }[/tex]*[tex]5^{-1 }[/tex]=[tex]5^{x }[/tex]*[tex]\frac{1}{5}[/tex]

[tex]\frac{1}{5}[/tex]([tex]5^{x }[/tex])=11

[tex]5^{x}[/tex]=55

[tex]5^{x+1}[/tex]=[tex]5^{x}[/tex]*5=55*5=275

x=[tex]log_{5 }[/tex](55)

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