Writing the equations

[Guest]

I am having 2 data
one is time data(x)
Another one is corresponding value(y)
Linearly varied to the time function

y= 1 to 10
x= 1 to 100
x value linearly varied to 90s

Can we write equations to plot linear graph?

[Guest]

The linear equation that relates x and y is:

y = mx + b

Where:

y is the corresponding value.
x is the time data.
m is the slope of the line (how much y changes per unit change in x).
b is the y-intercept (the value of y when x is 0).
To find the values of m and b for our specific case, we can use the given information about y and x:

Given:

y varies from 1 to 10
x varies from 1 to 100 over a 90-second interval
We can find the slope (m) as follows:

m = (change in y) / (change in x)
m = (10 - 1) / (100 - 1)
m = 9 / 99
m ≈ 0.0909

Now, we can find the y-intercept (b) using one of the points (1, 1) or (100, 10):

Using (1, 1):
y = mx + b
1 = (0.0909)(1) + b
1 = 0.0909 + b
b = 1 - 0.0909
b ≈ 0.9091

So, the linear equation to plot the graph is:

y = 0.0909x + 0.9091

Now, you can use this equation to plot the linear graph for the given data and time interval (x from 1 to 100, y from 1 to 10 over 90 seconds).

[Guest]

Yes, you can write an equation to plot a linear graph using the given data. Since the relationship between x and y is linear, you can use the equation of a straight line, which is:

y=mx+b

Where:

• m is the slope of the line
• b is the y-intercept

In this case, since y varies from 1 to 10 as x varies from 1 to 100 linearly over 90 seconds, we can determine the slope (m) and y-intercept (b) using the given data.
The slope (m) can be calculated as the change in y divided by the change in x:

m=Δy/Δx
m=10−1/100−1=9/99

The y-intercept (b) can be determined by substituting the values of x and y into the equation and solving for b:

1=999×1+b
b=1−9/99

Now, you can plug the values of m and b into the equation y=mx+b to get the equation of the line. Then you can use this equation to plot the linear graph.

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[GeradHum]

Yes! You can write a linear equation like:

y = m * x + b

where m = (10 - 1) / (100 - 1) = 9/99 ≈ 0.0909,
and b = starting y value (1).

So,
y ≈ 0.0909 * x + 0.909

This will plot y increasing linearly from 1 to 10 as x goes from 1 to 100.