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by nycmath » Wed Sep 02, 2026 6:28 am
Solve for z.
x^3 + y^3 + z^3 = 29
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nycmath
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by Eigenvalue » Wed Sep 02, 2026 7:48 am
x³+y³+z³=29
z³=29-x³-y³
z=[tex]\sqrt[3]{29-x³-y³}[/tex]
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Eigenvalue
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