by nycmath » Mon Sep 21, 2026 11:20 pm
by Eigenvalue » Tue Sep 22, 2026 1:20 am
by nycmath » Tue Sep 22, 2026 2:16 am
Eigenvalue wrote:[tex]\sqrt{36}[/tex]=6[tex]\sqrt{16}[/tex],=4[tex]\sqrt{4}[/tex]=2[tex]\frac{ \sqrt{36} + \sqrt{16} }{ \sqrt{4} }[/tex]=[tex]\frac{6+4}{2}[/tex]=5
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