# Find the polynomial function

### Find the polynomial function

Find the polynomial function f with real coefficients that has the given degree, zeros, and solution point.
Degree: 3
Zeros: -3, 1+$$\sqrt{3}i$$
Solution Point: f(−2) = 12
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### Re: Find the polynomial function

Any cubic function can be written f(x)= a(x- b)(x- c)(x- d) where b, c, and d are zeros of the function. Since the coefficients are required to be real and $$1+ i\sqrt{3}$$ is a root, its complex conjugate, $$1- i\sqrt{3}$$ is also. A cubic function with those zeros is of the form $$f(x)= a(x+ 3)(x-1-i\sqrt{3})(x-1+\sqrt{3})$$.

The fact that f(-2)= 12 means that $$f(-2)= a(-2+ 3)(-2-1-i\sqrt{3})(-2-1+\sqrt{3})= a(-3- i\sqrt{3})(-3+i\sqrt{3})= 12$$. Solve that equation for a.

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