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If f(x) = int(x/2), find
(a) f(1.2)
(b) f(1.6)
(c) f(-1.45)
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Greatest Integer Function
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Re: Greatest Integer Function
by Eigenvalue » Fri Aug 14, 2026 8:20 pm
A) f(x)=int(x/2)
x=1.2
f(x)=int(1.2/2)=0
B) f(x)=int(x/2)
x=1.6
f(x)=int(1.6/2)=0
C) f(x)=int(x/2)
x=-1.45
f(x)=int(-1.45/2)=0
x=1.2
f(x)=int(1.2/2)=0
B) f(x)=int(x/2)
x=1.6
f(x)=int(1.6/2)=0
C) f(x)=int(x/2)
x=-1.45
f(x)=int(-1.45/2)=0
- Eigenvalue
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Re: Greatest Integer Function
by nycmath » Fri Aug 14, 2026 8:31 pm
Eigenvalue wrote:A) f(x)=int(x/2)
x=1.2
f(x)=int(1.2/2)=0
B) f(x)=int(x/2)
x=1.6
f(x)=int(1.6/2)=0
C) f(x)=int(x/2)
x=-1.45
f(x)=int(-1.45/2)=0
Great. That was easy enough. Just plug and chug.
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