Compute

Compute

Postby nycmath » Fri Sep 25, 2026 10:44 pm

See attachment.
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nycmath
 
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Re: Compute

Postby Eigenvalue » Sat Sep 26, 2026 12:04 am

y=[tex]( \sqrt{3}) ^{4π }[/tex]=[tex]3^{2π }[/tex]

[tex]\sqrt{4-y²}[/tex]=[tex]\sqrt{4-(3 x^{2π})² }[/tex]
=[tex]\sqrt{4- 3^{4π } }[/tex]

Note: this expression is simplifiable, yet simplifying it does not greatly impact the result

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Re: Compute

Postby nycmath » Sat Sep 26, 2026 10:58 am

Eigenvalue wrote:y=[tex]( \sqrt{3}) ^{4π }[/tex]=[tex]3^{2π }[/tex]

[tex]\sqrt{4-y²}[/tex]=[tex]\sqrt{4-(3 x^{2π})² }[/tex]
=[tex]\sqrt{4- 3^{4π } }[/tex]

Note: this expression is simplifiable, yet simplifying it does not greatly impact the result


That's what makes it interesting. I think this is a David Cohen question.

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