Proof for the collatz conjecture?

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What does a proof to the collatz conjecture look like? Could the insight below be on its way to become a proof?

Start with any number n, whether it is odd or even, we get n/1 equals n. In the examples below, there is n/1, n/2, n/4, and this translates to equation n/x. The limit of n/x is equal to 1. So the conjecture will always go to 1 no matter what number you start out with. This is for even numbers and when working with multiplication/division there is a higher probability of getting an even number as seen in the multiplication table. There is a higher probability of divisions in the conjecture so the conjecture will eventually traject downwards toward its limit.

The randomness of that trajectory comes from the odd numbers or from the limits of the other equations in the conjecture. There are the equations n/1 and 3n+1 in which the limits go to infinity. There is (3n+1)/1, (3n+1)/2, (3n+1)/4, and this translates to (3n+1)/x whose limit is undetermined (3, infinity, or 0 if not 1). This indeterminate limit and the presence of the limits of multiple equations or the odd numbers could cause the randomness. The trajectory and loop at 1 could be caused by the limit of n/x which equals 1 and this limit of n/x determines the limit of (3n+1)/x which then equates to 1. (3n+1)/x = n/x as seen in the equations in the examples below.

If (3n+1)/x = n/x then the limit of (3n+1)/x = the limit of n/x which is 1. The conjecture will always reach 1 because of that limit.

Example:

n=28 —> n/1 =28
n=3 —> n/1=3

For the conjecture we get:

n=28 —> n/1=28 (even)

28/2=14 —> n/2=14 (even)

14/2=7 —> n/4=7 (odd)

(3•7)+1=22 —> (3n+1)/1=22 (even)

22/2=11 —> (3n+1)/2=11 —> n/2=11 (odd)

(3•11)+1=34 —> (3n+1)/1=34 (even)

34/2=17 —> (3n+1)/2=17 —> n/2=17 (odd)

(3•17)+1=52 —> (3n+1)/1=52 (even)

52/2=26 —> (3n+1)/2=26 —> n/2=26 (even)

26/2=13 —> (3n+1)/4=13 —> n/4=13 (odd)

(3•13)+1=40 —> (3n+1)/1=40 (even)

40/2=20 —> (3n+1)/2=20 —> n/2=20 (even)

20/2=10 —> (3n+1)/4=10 —> n/4=10 (even)

10/2=5 —> (3n+1)/8=5 —> n/8=5 (odd)

(3•5)+1=16 —> (3n+1)/1=16 (even)

16/2=8 —> (3n+1)/2=8 —> n/2=8 (even)

8/2=4 —> (3n+1)/4=4 —> n/4=4 (even)

4/2=2 —> (3n+1)/8=2 —> n/8=2 (even)

2/2=1 —> (3n+1)/16=1 —> n/16=1 (odd)

(3•1)+1=4 —> (3n+1)/1=4 (even)

4/2=2 —> (3n+1)/2=2 —> n/2=2 (even)

2/2=1 —> (3n+1)/4=1 —> n/4=1 (odd)

Example 2:

n=3 —> n/1=3 (odd)

(3•3)+1=10 —> (3n+1)/1=10 (even)

10/2=5 —> (3n+1)/2=10 —> n/2=5 (odd)

(3•5)+1=16 —> (3n+1)/1=16 (even)

16/2=8 —> (3n+1)/2=8 —> n/2=8 (even)

8/2=4 —> (3n+1)/4=4 —> n/4=4 (even)

4/2=2 —> (3n+1)/8=2 —> n/8=2 (even)

2/2=1 —> (3n+1)/16=1 —> n/16=1 (odd)

(3•1)+1=4 —> (3n+1)/1=4 (even)

4/2=2 —> (3n+1)/2=2 —> n/2=2 (even)

2/2=1 —> (3n+1)/4=1 —> n/4=1 (odd)