If a, b, c form a geometric progression find a-b/b-c=?

[Guest]

If a, b, c form a geometric progression, find [tex]\frac{a-b}{b-c}=?[/tex]

[Guest]

If a, b, and c are in a geometric porgression then (b/a)=(c/b)=k then a-b/b-c=(a-ak)/(b-bk)=a(1-k)/b(1-k)=a/b

[Guest]

If they are formed geometric series, [tex]b=ak[/tex] and [tex]c=ak^{2}[/tex] then,

[tex](a-b)/(b-c)=(a-ak)/(ak-ak^{2})=a*(1-k)/[a*k*(1-k)]=1/k[/tex]

[Haider05]

The example above shows that arithmetic progression increases much slower than geometric progression.????


Ali

[Guest]

The answer would be 33