Finding n

Arithmetic and Geometric progressions.

Finding n

Postby inky » Wed Oct 13, 2010 7:41 am

a1=5
d=10

The sum is 3000 (ie. How long will it take to fall 3000m?)

Formula I have is Sn=n/2 (2a + (n-1)d)

so,

3000=n/2 (10 + (n-1)10)

Trouble is, I can't work out what n is.

I know that, from putting the series into Excel - 5,15,25,... and using a simple formula to calculate the sums as the series progresses that when n=25 the sum is 3125. But I need to be able to do it 'properly'.
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Postby Math Tutor » Wed Oct 13, 2010 2:20 pm

[tex]3000=\frac{n}{2 }(10 + (n-1)10)[/tex]

[tex]3000=\frac{10n}{2 }(1 + (n-1))[/tex]

[tex]3000=5n*n[/tex]

[tex]600=n^2[/tex]

n=24.4948........

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