Solve: x^6 + 3x^3 + 10 = 1

[Guest]

Someone please help me solve this.
Solve:  x^6 +  3x^3  + 10 = 1

[adamsmith]

Given x^6 +3x^3+ 10 =1
=>x^6+3x^3+9=0
=>(x^3-3/2)^2+27/4=0
we get 6 root for x
[tex]=>x=-\sqrt[3]{-\frac{3}{2} }\sqrt[3]{-1-i\sqrt{3}}[/tex]
[tex]=>x=-\sqrt[3]{-\frac{3}{2}(-1-i\sqrt{3})}[/tex]
x=³√(3/2(-1-i√3))
x=(-1)^2/3³√(3/2(-1-i√3))
x=-³√(-3/2)³√(-1+i√3)
x=³√(3/2(-1+i√3))
x=(-1)^2/3³√(3/2(-1+i√3))

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