by nycmath » Sat Aug 15, 2026 5:31 am
by Eigenvalue » Sat Aug 15, 2026 9:45 am
by nycmath » Sat Aug 15, 2026 11:31 pm
Eigenvalue wrote:r²=[tex]\frac{A}{ \pi }[/tex]r=[tex]\pm \sqrt{A/pi}[/tex]This can be simplified, yet the result remains the same
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