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Find k
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Re: Find k
by Eigenvalue » Tue Aug 25, 2026 8:21 pm
[tex]\frac{60}{80}[/tex] simplifies to [tex]\frac{3}{4}[/tex]
[tex]\frac{6k}{7}[/tex]=[tex]\frac{3}{4}[/tex]
24k=21
k=[tex]\frac{21}{24}[/tex]=[tex]\frac{7}{8}[/tex]
[tex]\frac{6k}{7}[/tex]=[tex]\frac{3}{4}[/tex]
24k=21
k=[tex]\frac{21}{24}[/tex]=[tex]\frac{7}{8}[/tex]
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Re: Find k
by nycmath » Tue Aug 25, 2026 8:22 pm
[quote="Eigenvalue"][tex]\frac{60}{80}[/tex] simplifies to [tex]\frac{3}{4}[/tex]
[tex]\frac{6k}{7}[/tex]=[tex]\frac{3}{4}[/tex]
24k=21
k=[tex]\frac{21}{24}[/tex]=[tex]\frac{7}{8}[/tex][/quote
Yes, that works.
[tex]\frac{6k}{7}[/tex]=[tex]\frac{3}{4}[/tex]
24k=21
k=[tex]\frac{21}{24}[/tex]=[tex]\frac{7}{8}[/tex][/quote
Yes, that works.
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