Properties of Prime Numbers and Nontrivial Zeta Zeros?

[FrederickCaleb]

Therefore, each prime number is unique, and so is its corresponding simple nontrivial zeta zero. The nontrivial zeta zeros are simple since their corresponding primes are also simple or unique. And primes span all the integers most efficiently according to the Prime Number Theorem.

Moreover, every positive integer, k >1, there exists a prime number, p, which divides k such that either p = k or p \displaystyle \le k^{1/2}≤k
1/2
. And therefore,

and that exponent of k which is the optimum 1/2 confirms the truth of the Riemann Hypothesis, Re(\displaystyle z_{n }z
n
​
) = 1/2.

Of course, there are 'authorities/experts' or nonbelievers who cannot accept the truth of Riemann Hypothesis for whatever fictional or personal reasons. And that's a sad truth for some unfortunately. Truth of the Riemann Hypothesis is much more than a sound assumption -- It's the truth! Thank Lord God! Amen!

[Guest]

Update:

... Therefore, the [tex]n^{th}[/tex] prime number is unique, and so is its corresponding simple nontrivial zeta zero, [tex]z_{n}[/tex]. The nontrivial zeta zeros are simple since their corresponding primes are also simple or unique. And primes span all the integers most efficiently according to the Prime Number Theorem.

Moreover, for every positive integer, k >1, there exists a prime number, p, that divides k such that either p = k or [tex]3 \le p \le k^{1/2}[/tex].

And therefore, and that exponent of k, [tex]\frac{1}{2}[/tex], is optimum, and it confirms the truth of the Riemann Hypothesis, Re([tex]z_{n} )[/tex] = [tex]\frac{1}{2}[/tex].

Of course, there are 'authorities/experts' or nonbelievers who cannot accept the truth of the Riemann Hypothesis for whatever fictional or personal reasons. And that's a sad truth for some, unfortunately.

The truth of the Riemann Hypothesis is much more than a sound assumption. It's the truth! Thank Lord God! Amen!

Yes! In Lord God and in the Riemann Hypothesis, we trust! Amen!

[Guest]

[Guest]

(Update: Two is prime too!)

... Moreover, for every positive integer, k >1, there exists a prime number, p, that divides k such that either p = k or [tex]2 \le p \le k^{\frac{1}{2}}[/tex]...