primework123 wrote:Keywords: Prime Number Theorem (PNT), the sound Goldbach Conjecture (GC),
[tex]\pi(*)[/tex] is the prime counting function; , Fundamental Theorem of Arithmetic, Number Theory, and Analysis/Synthesis,...
Prime Work:
(1) There are infinitely many more positive integers (even or odd) than there are prime numbers, or prime numbers have a zero density relative to the positive integers,
and
(2) prime numbers generate the positive even integers so efficiently that gaps between two consecutive prime numbers increase without bound.
(3) Prime Parity Law (PPL):
[tex]\pi(e = mg = 1 + p_{2n }) = 2 * \pi(g = 1 + p_{n }) = 2n[/tex] where
[tex]p_{n } > 2, p_{2n }[/tex] are odd prime numbers; [tex]2 < m ≤ 3[/tex]; and as [tex]g\rightarrow\infty[/tex], [tex]m \rightarrow 2[/tex].
...
Note: mpg' ( the
maximum prime gap between two consecutive prime numbers in the interval, [0, x ≥ 97] ) is calculated in accordance to the above laws for the distribution of prime numbers.
Let's Formulate an Uncertainty Principle (UCP) For Calculating the Exact Distribution of Odd Prime Numbers
(Hey, Quantum Physics has one!) until we can do better...
Keywords: Pi()--Odd Prime Counting Function, Li()--Logrithmatic Integral, ln()--natural log function, and pn and pn+1 are nth prime and (n+1)th prime, respectively, and we count 1 as prime only in the additive sense of number theory.
Here are some important facts we might considered provided Riemann Hypothesis (RH) is true (RH is true!):
*FACT I: |Pi(x) - Li(x)| < ( sqrt(x) * ln(x) ) / (8*[tex]\pi[/tex]) for all x ≥ 2657.
(*See Reference: Schoenfeld, Lowell (1976), "Sharper bounds for the Chebyshev functions θ(x) and ψ(x). II",
Mathematics of Computation 30 (134): 337–360, doi:10.2307/2005976, JSTOR 2005976, MR 0457374.)
FACT II: (?) or could it be the
Average Prime Gap Error (APGE) associated with the true average gap for all pn and pn+1 in the interval,
[1, x]?
FACT III: What could it be?
Uncertainty Principle (UCP) for the distribution of odd prime numbers:
UCP is |Pi(x) - Li(x)| * APGE ≥ ? for all x ≥ 2657.
Right? or Not even wrong!... !?
A Solution:Uncertainty Principle (UCP) is |Pi(x) - Li(x)| * |a'(x) - a(x)|. Calculation:We let
a'(x) = x/Pi(x) where
a'(x) is the true average prime gap for all pn and pn+1 in [1, x].
And we let
a(x) = x/Li(x) where
a(x) is the approximate average prime gap for all pn and pn+1 in [1, x].
|Pi(x) - Li(x)| * |a'(x) - a(x) | < ? where
|Pi(x) - Li(x)| < sqrt(x) * ln(x)/(8*[tex]\pi[/tex]) for all x ≥ 2657, and
APGE is |a'(x) - a(x)|, and [tex]\pi[/tex] = 3.14...
|Pi(x) - Li(x)| < sqrt(x) * ln(x)/(8*[tex]\pi[/tex]) implies Pi(x) = Li(x) + r * sqrt(x) * ln(x) / (8 *pi) where -1 < r < 1.
This last equation implies Pi(x) = (8 * [tex]\pi[/tex] * Li(x) + r * sqrt(x) * ln(x) )/(8 *[tex]\pi[/tex]).
Therefore,
a'(x) = x / Pi(x) = 8 * pi * x / (8 * [tex]\pi[/tex] * Li(x) + r * sqrt(x) * ln(x) ).
So, |a'(x) - a(x)| = |8 * [tex]\pi[/tex] * x / (8 * [tex]\pi[/tex] * Li(x) + r * sqrt(x) * ln(x)) - x / Li(x) |
= x / Li(x) * | (8 * [tex]\pi[/tex] * Li(x) - 8 * [tex]\pi[/tex] * Li(x) - r * sqrt(x) * ln(x))/ (8 *[tex]\pi[/tex] * Li(x) + r * sqrt(x) * ln(x)) |
= x / Li(x) * | ( - r * sqrt(x) * ln(x))/ (8 * [tex]\pi[/tex] * Li(x) + r * sqrt(x) * ln(x)) |
< x / Li(x) * | ( sqrt(x) * ln(x))/ (8 * [tex]\pi[/tex] * Li(x) - sqrt(x) * ln(x)) |
= x / Li(x) * ( sqrt(x) * ln(x))/ (8 * [tex]\pi[/tex] * Li(x) - sqrt(x) * ln(x)) if r = -1.
Therefore,
APGE is |a'(x) - a(x)| < x / Li(x) * | ( sqrt(x) * ln(x))/ (8 * [tex]\pi[/tex] * Li(x) - sqrt(x) * ln(x)) |.
Hence,
|Pi(x) - Li(x)| * |a'(x) - a(x) | < (sqrt(x) * ln(x)) /(8*[tex]\pi[/tex])) * x / Li(x) * ( sqrt(x) * ln(x))/ (8 *[tex]\pi[/tex] * Li(x) - sqrt(x) * ln(x))
= 1/(8 * [tex]\pi[/tex]) * 1/Li(x) * (x * ln(x))^2 / (8 * [tex]\pi[/tex] * Li(x) - sqrt(x) * ln(x)).
Thus, we have the following calculation of UCP**:
UCP is |Pi(x) - Li(x)| * |a'(x) - a(x) | < (x * ln(x) )^2 /[8 * [tex]\pi[/tex] * Li(x) * ( 8 * [tex]\pi[/tex] * Li(x) - sqrt(x) * ln(x) ) ].**Note: The Riemann Prime-Counting Function R(x) will improve UCP substantially because R(x) = Pi(x) since it incorporates all the
non-trivial zeta zeros of the Riemann zeta function in its calculation.
David Cole
(aka primework123)
Please support my research work at:
https://www.gofundme.com/david_coleThank you! Thank Lord GOD!
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