Guest wrote:"It's elementary, my dear friends."![]()
One is exceptional! Why?
For any rational numbers, a and b such that [tex]0 \le a, b \le 1[/tex], then [tex]1^{ab} = 1[/tex]
Guest wrote:The distribution of prime numbers and the distribution of the nontrivial zeros of the Riemann zeta function with analytic continuation are two sides of the same coin, the very important divergent Harmonic Series, and therefore, they must complement each other... RH is a structural necessity!
Guest wrote:Guest wrote:The distribution of prime numbers and the distribution of the nontrivial zeros of the Riemann zeta function with analytic continuation are two sides of the same coin, the very important divergent Harmonic Series, and therefore, they must complement each other... RH is a structural necessity!
[tex]\zeta(z = \frac{1}{2} ± bi, p) = \sum_{k=1}^{N}\frac{1}{(kp)^{ \frac{1}{2} ± bi}} + \gamma(\frac{1}{2} \mp bi) + \sum_{k=1}^{M}\frac{1}{(kp)^{ \frac{1}{2} \mp bi}} + R( \frac{1}{2} ± bi) = 0[/tex]
where z is the the simple nontrivial zero of the Riemann zeta function with analytic continuation and where p is the appropriate positive prime number.
Relevant Reference Link:
Riemann Siegel formula
Guest wrote:On the Importance of Montgomery's pair correlation conjecture:
...
https://www.quora.com/Why-must-Polignacs-conjecture-be-true/answer/David-Cole-or-Poet-Dave-Cole
Guest wrote:Guest wrote:On the Importance of Montgomery's pair correlation conjecture:
...
https://www.quora.com/Why-must-Polignacs-conjecture-be-true/answer/David-Cole-or-Poet-Dave-Cole
FYI:
What's the status of Montgomery's pair correlation conjecture?
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