Guest wrote:Guest wrote:Hmm. Solving for [tex]\beta_{1}[/tex] is unworkable. Right?
Can we estimate roughly the range of possible values for [tex]\beta_{1}[/tex] or [tex]\beta_{ 2}[/tex] by holding [tex]y[/tex] as a constant and by employing the Newton's Method?
It's worth a try.
We hold [tex]y[/tex] as a constant and vary the values of [tex]\beta_{ 2}[/tex] and determine the range of possible values for [tex]\beta_{1}[/tex].![]()
Or we hold [tex]y[/tex] as a constant and vary the values of [tex]\beta_{ 1}[/tex] and determine the range of possible values for [tex]\beta_{2}[/tex].
Let's generate some results. Good Luck!
Guest wrote:Remark: Our latest efforts are workable, but we can do better. We must do better!
Imagine a Diophantine equation with twenty or more unknown variables. How do we solve it?
Guest wrote:Remark: Solving (generally) Diophantine equations is a serious 'bookkeeping task'. The numbers (integers) must add up correctly, or they don't. Either way, "we must know, and we will know!" (David Hilbert)
Moreover, our bookkeeping will probably require matrices and some advanced tools of algebra.
Guest wrote:Guest wrote:Remark: Solving (generally) Diophantine equations is a serious 'bookkeeping task'. The numbers (integers) must add up correctly, or they don't. Either way, "we must know, and we will know!" (David Hilbert)
Moreover, our bookkeeping will probably require matrices and some advanced tools of algebra.
[tex]T: \mathbb {Z^{n }} \rightarrow \mathbb {Z}[/tex] or T(X) = [tex]k \in \mathbb{Z }[/tex] where X = ([tex]x_{1 }[/tex],[tex]x_{2 }[/tex], ..., [tex]x_{n }[/tex]) [tex]\in \mathbb{Z^{n } }[/tex].
Tentatively, some key topics may include perturbation theory, eigenvalues and eigenvectors, etc. where [tex]x \in[/tex] {[tex]x_{1 }[/tex],[tex]x_{2 }[/tex], ..., [tex]x_{n }[/tex]} and [tex]\lambda_{i}[/tex] are pivotal.
Guest wrote:Let X = ([tex]x_{1 }[/tex], [tex]x_{2 }[/tex], [tex]x_{3 }[/tex], [tex]x_{4 }[/tex], [tex]x_{5 }[/tex], [tex]x_{6 }[/tex], [tex]x_{7 }[/tex], [tex]x_{8 }[/tex], [tex]x_{9 }[/tex], [tex]x_{10 }[/tex], [tex]x_{11 }[/tex], [tex]x_{12 }[/tex], [tex]x_{13 }[/tex], [tex]x_{14 }[/tex], [tex]x_{15 }[/tex], [tex]x_{16 }[/tex], [tex]x_{17 }[/tex], [tex]x_{18 }[/tex], [tex]x_{19 }[/tex], [tex]x_{20 }[/tex]).
And we let
T(X) = [tex](3x_{1 } + 8 x_{5 }x_{6 } ) ( 14x_{3 }^3 - 56 x_{4 } x_{7 }) (2x_{4 } - 9x_{2 }^2 x_{9 }) (17x_{6 } - 61 x_{8} x_{11 }) ( x_{13} + x_{16 }^2-9 x_{14 } x_{18 }) ( x_{12 } - 9 x_{15 } x_{19 })(x_{10 } - 9 x_{17 } x_{20 })-4,034,500,221x_{1}^2x_{4}x_{7}^3x_{9}x_{10}^2x_{18}x_{20}^3[/tex].
We must compute the following partial derivatives of T(X). (Why?We need to know how T(X) generally behaves.)
[tex]\frac{\partial T}{\partial x_{1 } } = ?[/tex]
[tex]\frac{\partial T}{\partial x_{2 } } = ?[/tex]
[tex]\frac{\partial T}{\partial x_{3} } = ?[/tex]
[tex]\frac{\partial T}{\partial x_{4 } } = ?[/tex]
[tex]\frac{\partial T}{\partial x_{5 } } = ?[/tex]
[tex]\frac{\partial T}{\partial x_{6} } = ?[/tex]
[tex]\frac{\partial T}{\partial x_{7} } = ?[/tex]
[tex]\frac{\partial T}{\partial x_{8 } } = ?[/tex]
[tex]\frac{\partial T}{\partial x_{9 } } = ?[/tex]
[tex]\frac{\partial T}{\partial x_{10 } } = ?[/tex]
[tex]\frac{\partial T}{\partial x_{11} } = ?[/tex]
[tex]\frac{\partial T}{\partial x_{12 } } = ?[/tex]
[tex]\frac{\partial T}{\partial x_{13 } } = ?[/tex]
[tex]\frac{\partial T}{\partial x_{14 } } = ?[/tex]
[tex]\frac{\partial T}{\partial x_{15} } = ?[/tex]
[tex]\frac{\partial T}{\partial x_{16 } } = ?[/tex]
[tex]\frac{\partial T}{\partial x_{17 } } = ?[/tex]
[tex]\frac{\partial T}{\partial x_{18 } } = ?[/tex]
[tex]\frac{\partial T}{\partial x_{19} } = ?[/tex]
[tex]\frac{\partial T}{\partial x_{20 } } = ?[/tex]
Guest wrote:FYI: 'Partial Derivative',
https://en.wikipedia.org/wiki/Partial_derivative.
Are we missing the point, X, for T(X) = k?![]()
Time will tell.
Guest wrote:Remark: The existence and uniqueness of solutions are important!
Guest wrote:Guest wrote:Remark: The existence and uniqueness of solutions are important!
There may be solutions galore, [tex]X \in \mathbb{R^{n}}[/tex], such that T(X) = k. But there could also be no solutions, [tex]X \in \mathbb{Z^{n}}[/tex], such that T(X) = k.
Go figure!
Guest wrote:Guest wrote:Guest wrote:Remark: The existence and uniqueness of solutions are important!
There may be solutions galore, [tex]X \in \mathbb{R^{n}}[/tex], such that T(X) = k. But there could also be no solutions, [tex]X \in \mathbb{Z^{n}}[/tex], such that T(X) = k.
Go figure!
Exhaustive Search:
We assume T(X) = k and [tex]X \notin \mathbb{Z^{n}}[/tex].
Let [tex]X + \triangle X \ne X[/tex] such that T([tex]X + \triangle X[/tex]) = k.
Does the sum, [tex]X + \triangle X \in \mathbb{Z^{n}}[/tex]?
It's time to do some computing. Good Luck!
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