\rightarrow\gamma
Some Food for Thought:
Hmm. We have extracted our important equation ("
A Brief Analysis of the Collatz Conjecture"):
[tex]n_{t } = r_{t } * \prod_{j=1}^{t }(\frac{3}{2^{i_{j }}}) = r * \prod_{m=1}^{k }(\frac{3}{2^{m}})^{\frac{t}{2^{m}}}[/tex] with [tex]r_{t } > r[/tex] where k = Floor( [tex]\frac{log(e_{max })}{log(2)}[/tex])
and where [tex]e_{max }[/tex] is the
maximum positive even integer in a Collatz sequence.
The set of all possible
maximum divisors for the
Collatz sequence of positive even integers is {[tex]2^{0}, 2^{1}, 2^{2}, ..., 2^{k}[/tex]}.
Remark: The existence of the maximum divisor, [tex]2^{0}[/tex], implies [tex]n_{t } = 2^{0} = 1[/tex].
So, the probability that the maximum divisor, [tex]2^{0}[/tex],
does not occur is
roughly [tex](\frac{k}{k+1})^{\gamma}[/tex] for any closed cycle in a
Collatz sequence of positive even integers.
Remark: "Roughly" indicates a crude approximation.
But as [tex]\gamma \rightarrow \infty[/tex], [tex](\frac{k}{k+1})^{\gamma} \rightarrow 0[/tex].
Therefore, [tex]n_{t } = 1[/tex]. And we conclude the Collatz conjecture is true!
Remark: Our "food for thought" (analysis) may be over the 'top'... It's Ok!