Guest wrote:[tex]c_{1 }(log X)^{2} \le G(X) \le c_{2 }(log X)^{2}[/tex]
where [tex]0 < c_{1 } < c_{2} \le 1[/tex].
And for large X, [tex]\pi(X) >> log^{2}X[/tex].
Guest wrote:Guest wrote:[tex]c_{1 }(log X)^{2} \le G(X) \le c_{2 }(log X)^{2}[/tex]
where [tex]0 < c_{1 } < c_{2} \le 1[/tex].
And for large X, [tex]\pi(X) >> log^{2}X[/tex].
Proof of our claim that, [tex]G(X) < log^{2}X[/tex] for large X:
Keywords: Prime Number Theorem (PNT)
What constrains the size of G(X)?
The answer is the number, s, of smaller prime gaps between consecutive primes less than or equal to X.
But the average prime gap is size, [tex]\approx log X[/tex], since we exclude all prime gaps of size, G(X).
So, [tex]s * logX \approx X[/tex].
And b is the number of prime gaps of size, G(X).
Therefore, s * log X + b * G(X) = X. But, b << s,
generally.
So, we have,
s * log X + b * G(X) = X which implies
G(X) = (X - s * log X)/b = (X /(b * log X) - s/b) * log X
[tex]\approx[/tex] ([tex]\pi(X)/ b - s /b[/tex]) * log X.
We observe that, [tex]\pi(X) - s << \pi(X)[/tex]
and 0 < 1 / b < 1.
We know that log X << [tex]\pi(X)[/tex].
Hence,
[tex]G(X) \approx ( \pi(X) / b - s /b ) * log X < (log X) * log X
= log^{2}X[/tex].
Therefore, [tex]G(X) < log^{2}X[/tex].
Guest wrote:For large X, we have [tex]\pi(X) \approx X/log X[/tex] according to PNT where logX is the average gap size between consecutive primes less than or equal to X.
Now we let,
1. X = s * log X + b * [tex]log^{2}(X)[/tex], approximately.
We seek to show that equation one leads to a contradiction because of G(X) for some positive integers, s >> b.
Note: The integer constants, s and b, are the number of primes associated with the gap sizes, average and G(X), respectively.
Therefore, equation one implies,
2. [tex]X / log X \approx \pi(X) \approx s + b*log X = s + b * X / \pi(X)[/tex].
Moreover, equation two implies approximately,
3. [tex]\pi^{2}(X) - s* \pi(X) - b* X = 0[/tex].
In turn, equations, three and two, imply with the help of quadratic formula,
4. [tex]\pi(X) = \frac{s + \sqrt{s^{2} + 4bX}}{2} = s + b * log X[/tex].
However, equation four implies approximately,
5. X = s / 2 + b * [tex]log^{2} X[/tex] which contradicts equation one!
Thus, G(X) < [tex]log^{2} X[/tex] for large X.
Dave,
https://www.researchgate.net/profile/David_Cole29/amp
Guest wrote:Guest wrote:For large X, we have [tex]\pi(X) \approx X/log X[/tex] according to PNT where logX is the average gap size between consecutive primes less than or equal to X.
Now we let,
1. X = s * log X + b * [tex]log^{2}(X)[/tex], approximately.
We seek to show that equation one leads to a contradiction because of G(X) for some positive integers, s >> b.
Note: The integer constants, s and b, are the number of primes associated with the gap sizes, average and G(X), respectively.
Therefore, equation one implies,
2. [tex]X / log X \approx \pi(X) \approx s + b*log X = s + b * X / \pi(X)[/tex].
Moreover, equation two implies approximately,
3. [tex]\pi^{2}(X) - s* \pi(X) - b* X = 0[/tex].
In turn, equations, three and two, imply with the help of quadratic formula,
4. [tex]\pi(X) = \frac{s + \sqrt{s^{2} + 4bX}}{2} = s + b * log X[/tex].
However, equation four implies approximately,
5. X = (s / 2) * log X + b * [tex]log^{2} X[/tex] which contradicts equation one!
Thus, G(X) < [tex]log^{2} X[/tex] for large X.
Dave,
https://www.researchgate.net/profile/David_Cole29/amp
Note Change:
"In turn, equations, three and two, imply with the help of quadratic formula,"
Guest wrote:Oops! Proof is still wrong!!
Dave.
Guest wrote:"LARGE GAPS BETWEEN CONSECUTIVE PRIME NUMBERS: by Authors,
KEVIN FORD, BEN GREEN, SERGEI KONYAGIN, AND TERENCE TAO.
ABSTRACT. Let G(X) denote the size of the largest gap between consecutive primes below X. Answering a question of Erdos, we show that
[tex]G(X) \ge f(X) * \frac{\log X \log \log X \log \log \log \log X }{(\log \log \log X)^{2}}[/tex],
where f(X) is a function tending to infinity with X. Our proof combines existing arguments with a random construction covering a set of primes by arithmetic progressions. As such, we rely on recent work on the existence and distribution of long arithmetic progressions consisting entirely of primes."
Source:
https://arxiv.org/abs/1408.4505
Dave wrote:Dave wrote:"LARGE GAPS BETWEEN CONSECUTIVE PRIME NUMBERS: by Authors,
KEVIN FORD, BEN GREEN, SERGEI KONYAGIN, AND TERENCE TAO.
ABSTRACT. Let G(X) denote the size of the largest gap between consecutive primes below X. Answering a question of Erdos, we show that
[tex]G(X) \ge f(X) * \frac{\log X \log \log X \log \log \log \log X }{(\log \log \log X)^{2}}[/tex],
where f(X) is a function tending to infinity with X. Our proof combines existing arguments with a random construction covering a set of primes by arithmetic progressions. As such, we rely on recent work on the existence and distribution of long arithmetic progressions consisting entirely of primes."
Source:
https://arxiv.org/abs/1408.4505
A Comment:
The expression or dreadful idea, [tex]f( X) * \frac{\log X \log \log X \log \log \log \log X }{(\log \log \log X)^{2}}[/tex],
is an example of ugly/bizarre mathematics which fails miserably to capture the nature or truth about the largest gap between consecutive primes below large X. Personally, I reject that dreadful idea, and I could not force myself to read the paper beyond its abstract. The paper should have been rejected for publication. And shame on its authors!
Dave.
Relevant Reference Link:
'Mathematics must maintain its purity.',
https://www.math10.com/forum/viewtopic.php?f=63&t=8270.
Guest wrote:Yes! G(X) [tex]\le log^{2} X[/tex] for large X where [tex]G(X) \rightarrow log^{2} X[/tex] as [tex]X \rightarrow \infty[/tex].
Dave.
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