by Ellery Cade » Mon Jan 24, 2011 1:44 am
Factoring all the numbers into primes:
t e^2 n = 2^2 * 13
t^2 i l = 7 * 11
t a l^2 = 3 * 11^2
From the second of these equations, it is clear that t = 1, otherwise there would be a prime number with exponent >= 2 in the right-hand-side. Assuming different letters stand for different numbers, we now also know that l = 11 (from second and third equation). This gives us a = 3, i = 7. If all numbers are different, e can only be 2.
So tattle becomes t^3 a l e = 1^3 * 3 * 11 * 2 = 66.