FINDING MEETING POINT

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FINDING MEETING POINT

Postby rameshppc » Thu Aug 30, 2018 10:47 am

"A","B","C" STARTS AT THE SME TIME IN THE SAME DIRECTION TO RUN AROUND A RECTANGULAR GARDEN. "A" COMPLETES ONE FULL ROUND IN 252 SECONDS, "B" IN 308 SECONDS AND "C" IN 198 SECONDS. AFTER, WHAT TIME WILL THEY MEET AGAIN AT THE SAME STARTING POINT?

This question is really challenging for me to arrive the answer but not you.

Thanks for your time to solve my problems...
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Re: FINDING MEETING POINT

Postby Guest » Thu Aug 30, 2018 8:51 pm

The three will meet in 2 772 second .Is this the answer ?
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Re: FINDING MEETING POINT

Postby rameshppc » Fri Aug 31, 2018 7:08 am

Oh... you are great... Can you pls send me the steps. I want to know how its derived...

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Re: FINDING MEETING POINT

Postby Guest » Fri Aug 31, 2018 11:49 pm

I think like this:
"А" 252=2.2.3.3.7 (sec.) ; "B" 308=2.2.7.11 (sec.) ; "C " 198=2.3.3.11 (sec.)
We are looking for a number that is divided by 252 and 308 and 198.
It is 2.2.3.3.7.11=2 772 (seconds)
After 2 772 (sec.) the subject of "A" will have traveled 11 times and will be at the starting point.
After 2 772 (sec.) the subject of "B" will have traveled 9 times and will be at the starting point.
After 2 772 (sec.) the subject of "C" will have traveled 14 times and will be at the starting point.

The three objects will meet simultaneously at the starting point itself,from they left.
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Re: FINDING MEETING POINT

Postby rameshppc » Fri Sep 07, 2018 8:18 am

noted and understand, how to do it this sum

Thanks for your valuable information

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