Help with integrals

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Help with integrals

Postby Brycen Sanders » Sun May 15, 2022 4:02 am

Hi there!
I will be grateful for your help in solving this calculation.

Evaluate the integral. (Use C for the constant of integration.)

[tex]\int[/tex]ln([tex]\sqrt{x}[/tex])dx
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Re: Help with integrals

Postby Math Tutor » Sun May 15, 2022 7:22 am


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Re: Help with integrals

Postby nathi123 » Mon May 16, 2022 1:40 pm

If I = [tex]\int ln( \sqrt{x})dx = xln \sqrt{x} - \int \frac{xdx}{ \sqrt{x} .2 \sqrt{x} }=xln \sqrt{x} - \frac{1}{2} \int dx=xln \sqrt{x} - \frac{x}{2} +C[/tex].
We use that [tex]\int fdg=f.g - \int gdf[/tex]

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Re: Help with integrals

Postby Guest » Fri May 27, 2022 1:57 am

Brycen Sanders wrote:Hi there!
I will be grateful for your help in solving this calculation.

Evaluate the integral. (Use C for the constant of integration.)

[tex]\int[/tex]ln([tex]\sqrt{x}[/tex])dx


How did you start solving this task?
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Re: Help with integrals

Postby Guest » Fri May 27, 2022 2:06 am

Brycen Sanders wrote:Hi there!
I will be grateful for your help in solving this calculation.

Evaluate the integral. (Use C for the constant of integration.)

[tex]\int[/tex]ln([tex]\sqrt{x}[/tex])dx

Friend, hello. I saw your request here and on another resource and decided to write to you that decided your task. At https://plainmath.net/15991/evaluate-the-integral-use-for-the-constant-of-integration-int-ln-sqrt-dx you can see a complete and detailed explanation and solution of this integral definition.
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