# Problem on rectangle

### Problem on rectangle

The length of a rectangle is 4 times its breadth. If the length of its diagonal is 4 root17 wt is its perimeter and area
Guest

### Re: Problem on rectangle

Guest wrote:The length of a rectangle is 4 times its breadth. If the length of its diagonal is 4 root17 wt is its perimeter and area

It's quit easy

In rectangle ABCD,
.
suppose breadth of the rectangle=b AB=b . . BC=length=4b

Given:AC=4 root 17

Therefor square of AC=square of AB and square of BC
=4 root 17 square's=b square + 4b whole square

On further simplification

16*17=17b square

16*17/17=b square

16=b square
therefore b=4

therefore AB=b=4 and BC=4b=4*4=16

area=l*b
=16*4
=64

perimeter=2[l+b]
=2[4+16]
=2[20]
=40

hope u understand

bhavyashah9872

Posts: 2
Joined: Sun Mar 10, 2013 12:18 pm
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### Re: Problem on rectangle

The area is 64 and the perimeter 40.
Guest

### Re: Problem on rectangle

AC= 4 root 17

perimeter=2[l+b]
=2[4+16]
=2[20]
=40

The area of the rectangle will be 64 and perimeter will be 40.

leesajohnson

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Joined: Thu Dec 31, 2015 7:11 am
Location: London
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### Re: Problem on rectangle

Guest wrote:The area is 64 and the perimeter 40.
Guest