MV RAO wrote:ABCD is a trapezium with AB parallel to CD. Angle bisector of A meets DC at P and angle bisector of C meets AB at Q. Prove that APCQ is a parellogram.
martin123456 wrote:MV RAO wrote:ABCD is a trapezium with AB parallel to CD. Angle bisector of A meets DC at P and angle bisector of C meets AB at Q. Prove that APCQ is a parallelogram.
let [tex]\angle{A}=2\alpha[/tex]. AB||CD =>[tex]\angle{DPA}=\alpha[/tex]. Analog, let [tex]\angle{BCD}=2\beta[/tex]=>[tex]\angle{CQB}=\beta[/tex]. we have to prove that [tex]\alpha+\beta=\pi[/tex].
i think this is not true
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