by leesajohnson » Fri Jul 01, 2016 4:31 am
a+b = 3 ---- (i)
-b + c = 3 -----(ii)
a + 2c =10 ------(iii)
From the equation (i) we get
b = 3 - a
Now put the value of b into the 2nd equation
-(3-a) + c = 3
c = 3 + 3 - a
c = 6-a
Now we will put value of c into 3rd equation
a+ 2(6-a) = 10
a + 12 - 2a = 10
-a=10 -12
-a= -2
a=2
value of a = 2
put the value of "a" into equation 1st equation
2+ b =3
b= 3-2
b= 1
Now we will put the value of b into 2nd equation
-1 + c= 3
c= 3+1
c= 4
We have found out the value of a,b and c now and values are a = 2, b = 1, c = 4