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Substitution Method
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Re: Substitution Method
by Eigenvalue » Sun Aug 23, 2026 11:26 am
A.4(2w-1)+3(z+2)=48
8w-4+3z+6=48
8w+3z=46
3(w+3)-2(w-z)=18
3w+9-2w+2z=18
w+2z=9
w=9-2z
8(9-2z)+3z=46
72-13z=46
13z=26
z=2
w=5
8w-4+3z+6=48
8w+3z=46
3(w+3)-2(w-z)=18
3w+9-2w+2z=18
w+2z=9
w=9-2z
8(9-2z)+3z=46
72-13z=46
13z=26
z=2
w=5
- Eigenvalue
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Re: Substitution Method
by nycmath » Sun Aug 23, 2026 12:25 pm
Eigenvalue wrote:A.4(2w-1)+3(z+2)=48
8w-4+3z+6=48
8w+3z=46
3(w+3)-2(w-z)=18
3w+9-2w+2z=18
w+2z=9
w=9-2z
8(9-2z)+3z=46
72-13z=46
13z=26
z=2
w=5
Rhe first step is to simplify to remove the algebraic fractions.
Interesting.
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