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logarithms

Postby Blah » Wed Jan 06, 2010 9:09 pm

log2 ( 9-2^x) = 10 ^(log(3-x))
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Re: logarithms

Postby Blah » Wed Jan 06, 2010 9:12 pm

Blah wrote:log2 ( 9-2^x) = 10 ^(log(3-x))


the question is solve what x is

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