Can we canculate this angle and arc?

[Guest]

Dear Teacher

I would appreciate it, if you could solve my problem. Attached in the file

Sincerely,

AR

[Guest]

Dear Teacher

I would appreciate it, if you could solve my problem. Attached in the file

Sincerely,

AR

Email: arahma03@nyit.edu

[Guest]

ACD is 30 degrees.....you tell us that in the question
ACD is an isosoles triangle..2 equal sides...2 equal angles..
ADC is = (180 - 30) / 2 = 80 degrees
ADB then is = 100 degrees

Measurement Arc + BD = 10 + 10 = 20 ... you told us that in the question

[Guest]

Sorry a slip up in last post...... correction as below...

ACD is 30 degrees.....you tell us that in the question
ACD is an isosoles triangle..2 equal sides...2 equal angles..
ADC is = (180 - 30) / 2 = 75 degrees
ADB then is = 105 degrees

Measurement Arc + BD = 10 + 10 = 20 ... you told us that in the question

[leesajohnson]

ADB= 100 degrees

[Guest]

Lisa...... Did you read the question and the previous posted answers...?????

The angle ABD is 105 degrees as shown on the post before yours......

AD is a chord of length 10 cm

The length of the curved arc between A-D will be Radius x (30 degrees expressed as radians) = ??

You need to find the radius first........

[Guest]

Sorry typo in last post.....
It should read......
The angle ADB is 105 degrees as shown on the post before yours......

[Guest]

What questions are you asking?????????????????

See attached for 2 scenarios of this question.............

[Guest]

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