# Word problem

### Word problem

Hi, I’m struggling with this problem so any help would be much appreciated.
Four friends are sharing out football stickers from last season. Alec has seven more than one quarter of the stickers; Katie has three less than one sixth of the stickers; John has four fifths of the amount Alec has and Nick has nine more than John. How many football stickers were there altogether?
Guest

### Re: Word problem

Looks like a pretty standard algebra problem where the first thing you need to do is change from "sentences" to "equations"! The problem is to determine "How many football stickers were there altogether?" so let "N" be the total number of football stickers.

"Alec has seven more than one quarter of the stickers"
One quarter of the stickers is N/4. Seven more than that is N/4+ 7.
So Alec has N/4+ 7 stickers.

"Katie has three less than one sixth of the stickers"
"One sixth of the stickers" is N/6. 3 less than that is N/6- 3.
So Katie has N/6- 3 stickers.

"John has four fifths of the amount Alec has"
Alec has N/4+ 7 stickers so Alec has (4/5)(N/4+ 7)= N/5+ 28/5 stickers.

"Nick has nine more than John"
John has N/5+ 28/5 stickers so Nick has N/5+ 28/5+ 9= N/5+ 28/5+ 45/5= N/5+ 73/5 stickers.

Since these four people have all N stickers, the sum of each of these numbers must be N:
(N/4+ 7)+ (N/6- 3)+ (N/5+ 28/5)+ (N/5+ 73/5)= N
[N/4+ N/6+ N/5+ N/5]+ [7- 3+ 28/5+ 73/5]= N

To add the fractions, we need to get a common denominator:
4= 2*2 and 6= 2*3 so to get all the prime factors we need 2*2*3*5= 60.
N/4= 15N/60, N/6= 10N/60, and N/5= 12N/60
N/4+ N/6+ N/5+ N/5= (15N+ 10N+ 12N+ 12N)/60= 49N/60.

28/5+ 73/5= 101/5. 7- 3+ 28/5+ 73/5= 4+ 101/5= (20+ 101)/5= 121/5
49N/60+ 121/5= N

Subtract 49N/60 from both sides:
121/5= 11N/60 so 11N= (121)(12) and then N= 11(12)= 132.
There are a total of 132 football stickers.

Check:
"Alec has seven more than one quarter of the stickers"
1/4 of 132 is 33. Alec has 33+ 7= 40 stickers.

"Katie has three less than one sixth of the stickers"
1/6 of 132 is 22. Katie has 22- 3= 19 stickers.

"John has four fifths of the amount Alec has"
Alec has 40 stickers. 4/5 of 40 is 4(8)= 32. John has 32 stickers.

"Nick has nine more than John"
Nick has 32+ 9= 41 stickers.

Altogether there are 40+ 19+ 32+ 41= 132 stickers as needed!

HallsofIvy

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### Re: Word problem

Thank you so much, you made it look so easy
Guest

### Re: Word problem

Is there another way to get to the answer in this problem?

Johnnycol

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### Re: Word problem

Well, you could ask someone else to do it for you! That seems to be a popular method.

HallsofIvy

Posts: 159
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Reputation: 66