A right circular cone is inscribed in a sphere of radius 16 inches.
Express the volume of the cone as a function of it's altitude.
Please show full working out to show thought process of solving problem.
Thanks in advance
Guest wrote:How do you know that r=32-h
Did you prove it ?
I think you have a mistake here.
Guest wrote:Thanks to the last guest ! Through it i understood the reason-ing and the decision.
I think the solution is wrong ,because you are look private case .
The condition does not say that the radius of the cone is equal to the radius of the sphere.
If r(cone)=R(sphere)=h,then your solution will be true.
I will write the formula as follows:
V=[tex]\pi[/tex][tex]\frac{r^{2}h}{3}[/tex]=[tex]\pi[/tex][tex]\frac{16^{2}h}{3}[/tex]=[tex]\pi[/tex][tex]\frac{256h}{3}[/tex]
The formula you get is valid only for this particular case,when r=h=16 .
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