Equation with two variables

Equation with two variables

Postby MM » Fri Jul 25, 2008 3:37 pm

Prove that the equation [tex]x!=y^{2}[/tex] has no natural solutions.
User avatar
MM
 
Posts: 82
Joined: Tue Jul 22, 2008 7:36 am
Location: Bulgaria
Reputation: 9

Postby MM » Tue Aug 05, 2008 7:03 am

Solve the equation [tex]x!+1=y^{2}[/tex] in natural numbers.

User avatar
MM
 
Posts: 82
Joined: Tue Jul 22, 2008 7:36 am
Location: Bulgaria
Reputation: 9

Postby MM » Sat Aug 09, 2008 6:07 am

So there is a problem with the first equation. Fed_BG noticed it. So prove that there are no solutions for [tex]x\ge 2[/tex]

User avatar
MM
 
Posts: 82
Joined: Tue Jul 22, 2008 7:36 am
Location: Bulgaria
Reputation: 9

Re: Equation with two variables

Postby Blackcap145 » Mon Feb 23, 2015 3:29 am

Its to easy to solve it...!!! :lol:




_____________

Blackcap145
 
Posts: 1
Joined: Tue Feb 10, 2015 12:28 am
Reputation: 0

Re: Equation with two variables

Postby Guest » Sat Feb 20, 2016 9:11 am

[tex]x!=y^2[/tex] has no natural solutions for [tex]x>1[/tex] follows simply from Bertrand's postulate
https://en.wikipedia.org/wiki/Proof_of_ ... _postulate
[tex]x!+1=y^2[/tex] is Brocard's problem,
https://en.wikipedia.org/wiki/Brocard's_problem

R. Baber.
Guest
 

Re: Equation with two variables

Postby leesajohnson » Wed Mar 02, 2016 6:04 am

When x>1 then there is no natural solution for x!=y²
leesajohnson
 


Return to Math Olympiads



Who is online

Users browsing this forum: No registered users and 3 guests

cron