by shyamjayakannan » Fri Mar 13, 2026 2:59 pm
To find the maximum number of intersection points of n circles, we need to count all the distinct pairs of circles and multiply that by 2 because each pair gives 2 intersection points.
So, [tex]m=2{}^nC_2=2\times\frac{n!}{2!(n-2)!}=\boxed{n(n-1)}[/tex]