Calculate

Calculate

Postby Guest » Wed Nov 29, 2023 2:05 pm

A $\lambda$ sequence is an infinite sequence of complex numbers, so if the Culver sequence operator deletes all the O's and replaces each remaining number x with

$x - 3 + \frac{1}{x}$

then it gets the same sequence it started with.

Find the number of n-long sequences of complex numbers that form the beginning of some $\lambda$ -sequence.
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Re: Calculate

Postby Guest » Sat Apr 13, 2024 8:21 am

To find the number of n-long sequences of complex numbers that form the beginning of some λ-sequence after applying the Culver sequence operator, we need to understand how the operator behaves.

Let's denote the n-long sequence of complex numbers as (a_1, a_2, ..., a_n).

According to the given information, after applying the Culver sequence operator, each number x is replaced by (-3 + 1/(x-3)). So, for the sequence to remain unchanged, we need:

(-3 + 1/(a_1 - 3), -3 + 1/(a_2 - 3), ..., -3 + 1/(a_n - 3)) = (a_1, a_2, ..., a_n).

This implies:

-3 + 1/(a_i - 3) = a_i for all i from 1 to n.
Now, solving this equation for each a_i, we get:

-3 + 1/(a_i - 3) = a_i
=> 1/(a_i - 3) = a_i + 3
=> a_i - 3 = 1/(a_i + 3)
=> a_i + 3 = 1/(a_i - 3)

This shows that for the equation to hold true, each a_i must be reciprocal of (a_i - 3), and vice versa.

Thus, for each a_i in the sequence, a_i = 1/(a_i - 3). Solving this equation gives us a quadratic equation, which can have 0, 1, or 2 solutions for a_i.

Now, the number of n-long sequences of complex numbers that form the beginning of some λ-sequence would depend on how many solutions each term in the sequence has.

For instance:

If all terms have 0 solutions, it means they're not reciprocal to (a_i - 3), so they can be any complex number except 3.
If all terms have 1 solution, it means they're reciprocal to (a_i - 3), so they have a unique value determined by the equation.
If some terms have 2 solutions, it would make the λ-sequence ambiguous because there are two possible values for those terms, which would result in multiple sequences.
Therefore, the number of n-long sequences of complex numbers that form the beginning of some λ-sequence depends on how many terms have 0, 1, or 2 solutions for the equation a_i = 1/(a_i - 3). This count can be computed based on the properties of the solutions to the equation.

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